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Oksi-84 [34.3K]
3 years ago
12

If a balloon with a volume of 10L at 500kpa is heated until the balloon has a temperature of 300°C, 750atm and now has a volume

of 100mL. What was the original temperature of the balloon (in °C)
Chemistry
1 answer:
valentinak56 [21]3 years ago
5 0

Answer:

103.6°C

Explanation:

We solve this problem, with the Ideal Gases Law. We know that moles of gas are not changed through time.

P . V = n . R . T

So n (number of moles) and R (Ideal Gases constant) are the same, they are cancelled. In the two different states, we can propose:

P₁ . V₁ / T₁ = P₂ . V₂ /T₂

We need to make some conversions:

100 mL . 1 L/ 1000mL = 0.1L

500 kpa . 1atm / 101.3 kPa = 4.93 atm

300°C + 273 = 573 K

We replace data:

4.93 atm . 10L / T₂ = 750 atm . 0.1L / 573K

4.93 atm . 10L = (750 atm . 0.1L / 573K) . T₂

(4.93 atm . 10L) / (750 atm . 0.1L / 573K) → T₂

T₂ = 376.65 K

We convert K to °C →  376.65 K - 273 = 103.6 °C

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7nadin3 [17]

Answer:

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Explanation:

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7 0
4 years ago
Benzene is 92.3% carbon and 7.7% hydrogen. In anexperiment,
Marysya12 [62]

Answer:

The molecular formula of benzene = C_{6}H_{6}

Explanation:

Moles =\frac {Given\ mass}{Molar\ mass}

% of C = 92.3

Molar mass of C = 12.0107 g/mol

% moles of C = \frac{92.3}{12.0107} = 7.6848

% of H = 7.7

Molar mass of H = 1.00784 g/mol

% moles of H = \frac{7.7}{1.00784} = 7.6401

Taking the simplest ratio for C and H as:

7.6848 : 7.6401

= 1 : 1

The empirical formula is = CH

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12+ 1 = 13 g/mol

Molar mass = 78.0 g/mol

So,  

Molecular mass = n × Empirical mass

78.0 = n × 13

⇒ n ≅ 6

<u>The molecular formula of benzene = C_{6}H_{6}</u>

7 0
4 years ago
What is the temperature of a gas at STP?
Savatey [412]

Answer:

273 K

Explanation:

The temperature of a gas at STP is 273 K. This is equal to 0°C or 32°F.

3 0
3 years ago
What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O
nadya68 [22]

Answer:

V=43.46mL

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4

Then, given the molarity, it is possible to obtain the milliliters as follows:

V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL

Best regards!

7 0
3 years ago
4. The cloud of interstellar dust and gas that forms a star is known as
Ede4ka [16]
It's called a nebula or nebulae (plural). They are not only massive clouds of dust, hydrogen and helium gas, and plasma; they are also often “stellar nurseries” – i.e. the place where stars are born.
6 0
3 years ago
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