Question

Find the magnitude and direction (in degrees) of the vector. v = ‹ - sqrt(7)/9, - sqrt(2)/3 ›

Answer 1

The magnitude is given by:
 lvl = root ((- root (7) / 9) ^ 2 + (- root (2) / 3) ^ 2)
 lvl = 0.555555556
 The address is given by:
 cos (theta) = (- root (7) / 9) / (0.555555556)
 Clearing theta:
 theta = acos ((- root (7) / 9) / (0.555555556))
 theta = 121.95 degrees
 Answer:
 The magnitude and direction (in degrees) of the vector are:
 lvl = 0.555555556
 theta = 121.95 degrees