For number 1: you would add all the ages together, 23+19+50+49+67+34+30+59+40+33=404 and then divide that by how many workers(10) 404 divided by 10=40.4 and that is already rounded to the nearest tenth. So the answer to number 1 would be C. 40.4. Number 2: I'm just guessing but because the line on the graph shows is at around B) and C) is looks closer to $122 million, so I would go with D. $122 million
The solution of the given equation can be all real numbers, except c = 0 and c = 3.
Lets simplify the given problem,
1/c-3 - 1/c = 3/ (c-3)
As the denominators cannot be equal to zero (0) because a division by zero (0) is undefined.
Next, we would multiply both sides of the given by the lowest common multiple (LCM).
The lowest common multiple (LCM) is c(c - 3).
c-[c-3] = 3
c-c+3 = 3
0 = 3-3
0=0
Therefore, the solution of the given equation can be all real numbers, except c = 0 and c = 3.
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Here we have to figure out if 5 ones and 8 tenths is greater than or less than or equal to 58 tenths.
Now,
5 ones = 5
8 tenths 
Together, 5 ones and 8 tenths make
Now,
58 tenths 
We can see that 5 ones and 8 tenths and 58 tenths both are equivalent.
Therefore, 5 ones and 8 tenths is neither less nor greater than 58 tenths. They both are equal.
Answer:
I assume that there are parentheses missing from the question and that it should be
Prove that 1 + sin 2A + cos 2A ---------------------------------------------- = cot A
1+sin2A−cos 2A
Use sin 2 A= 2 sin A cos A and
cos 2 A = 1−2 sin 2 A and cos 2 A = 2 cos A−1
