2.At a local bank 7 out of 12 12 employees have a master's degree. If the bank has 100 employees,

Two triangles are similar, and the ratio of the corresponding sides is 1:5, and which of the following is true?

IrinaK [193]

Answer:

c

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the slope of the line going through the points (0, -5) and (-2,1)

kvasek [131]

Answer:

$\displaystyle m=-3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (0, -5)

Point (-2, 1)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m=\frac{-5-1}{0--2}$
[Fraction - Denominator] Simplify: $\displaystyle m=\frac{-5-1}{0+2}$
[Fraction - Numerator] Subtract: $\displaystyle m=\frac{-6}{0+2}$
[Fraction - Denominator] Add: $\displaystyle m=\frac{-6}{2}$
[Fraction] Divide: $\displaystyle m=-3$

8 0

2 years ago

HELP I WILL CHOOSE BRAINLIST

andrey2020 [161]

Answer:

I feel like its C or B

Step-by-step explanation:

6 0

2 years ago

Can 8x be added to 56? Why or why not? Use rich text?

Vladimir [108]

Answer:

see below

Step-by-step explanation:

8x and 56 are not like terms

x is a variable and 56 is a constant

8x can be added to 56 but they cannot be combined together into one term

8x+56 cannot be combined because they are not like terms

7 0

3 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

3 years ago