All categories

3 years ago

What is 5 ones and 8 tenths greater than or less than 58 tenths

Mathematics

1 answer:

lianna [129]3 years ago

8 0

Here we have to figure out if 5 ones and 8 tenths is greater than or less than or equal to 58 tenths.

Now,

5 ones = 5

8 tenths $=\frac{8}{10} =0.8$

Together, 5 ones and 8 tenths make

$5+0.8=5.8$

Now,

58 tenths $=\frac{58}{10} =5.8$

We can see that 5 ones and 8 tenths and 58 tenths both are equivalent.

Therefore, 5 ones and 8 tenths is neither less nor greater than 58 tenths. They both are equal.

You might be interested in

How do i do translation

igor_vitrenko [27]

Search on google “how do I do translation” an it depends on the subject.

6 0

4 years ago

Read 2 more answers

Marking as brainyest PLEASE HELP

trasher [3.6K]

Answer:

C) f(x) increases by 900%

Step-by-step explanation:

The rate of change is

f(4) - f(3)

---------------

4-3

f(4) = 9*4 = 36

f(3) = 9*3 = 27

36 -27

---------------

4-3

-----

The rate of change is 9

To change to a percent, multiply by 100%

9*100% = 900%

5 0

3 years ago

Read 2 more answers

13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult

Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that $\frac{ab}{m}$ is and integer.

As m= vb, then $\frac{m}{b}$ is an integer, lets say $\frac{m}{b}$ =v; and as m=ua, then $\frac{m}{a}$ =u.

So $\frac{ab}{m}$ v= $\frac{ab}{m}$ $\frac{m}{b}$ =a, so $\frac{ab}{m}$ divides a; on the other hand, $\frac{ab}{m}$ u= $\frac{ab}{m}$ $\frac{m}{a}$ =b, so $\frac{ab}{m}$ divides b. From this we can conclude that $\frac{ab}{m}$ is a common divisor of a and b.