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finlep [7]
3 years ago
6

Write the quadratic equation whose roots are 1 and −5, and whose leading coefficient is 4.

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

Standard Form: y = 4(x-1)(x+5)

Step-by-step explanation:

4 is the leading coefficient, so it should go in front. When making a standard quadratic equation, you must do the opposite for each of the roots (negative to positive, positive to negative.)

if you’re asking for a general form quadratic equation, then sorry, I am unable to help you with that :(

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How do you change 2/5 to a precent
nikklg [1K]

Answer:

40%

Step-by-step explanation:

Percent is how much out of 100.

We have 2/5, so find equivalent fractions:

2/5 = 4/10 = 40/100

2/5 = 40%

8 0
3 years ago
Kurt does chores in his neighborhood. The graph shows Kurt’s savings goal for the summer. If he washes 15 cars, how many lawns w
Dima020 [189]
25. Because (30/50)/(2)= 15/25
15= cars washed
25 = lawns mowed
8 0
3 years ago
Solve the systems of equations by substitution<br> 3/8x + 1/3y = 17/24<br> X + 7y = 8
Sedaia [141]

Answer:

If your solving for y...

The answer would be: y = -9/8x + 17/8 I believe.

For the second one... it would be : y = -1/7x + 8/7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
3.41 rounded to the nearest tenth please help
horrorfan [7]
Your answer would be 3.4

Anything under 5 it stays the same and anything over 5 it goes up one
5 0
3 years ago
Read 2 more answers
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } &#10;

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
3 years ago
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