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Deffense [45]
3 years ago
10

Fill in the blanks. # 3, 4, and 5

Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:i dont know

Step-by-step explanation:

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Can anyone help? I know it’s not A , but I need help . I’ll mark brainliest!
Paul [167]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
Find the x and y intercepts of 7x - 3y = 42
nlexa [21]

X int equal 6


y int equal -14

7 0
3 years ago
Please I NEED HELP ASAP <br>Graph the system of equations 2x+y=5; 14+7y=35
Luden [163]
You have to put it in Y=MX+B form, so that mean you subtract the 2x in the first equation and move it to the other side of the equal sign so it will look like this Y=2X+5 and for the second equation you do the same thing and thats your answer
5 0
4 years ago
Read 2 more answers
Find the center of the circle that you can circumscribe about DABC.
Vlada [557]

The center of the circle that circumscribe about DABC is (h,k) = (1, 5).

A circle can be modelled after a expression of the form:

A\cdot x + B\cdot y + C =-x^{2}-y^{2} (1)

We can determine all coefficients by knowing three <em>distinct</em> points on plane.

If we know that (x_{1}, y_{1}) = (2, 8), (x_{2}, y_{2}) = (0, 8) and (x_{3}, y_{3}) = (2, 2), then the solution of the system of linear equations is:

2\cdot A + 8\cdot B + C = -68 (2)

8\cdot B + C = -64 (3)

2\cdot A + 2\cdot B + C = -8 (4)

A = -2, B = -10, C = 16

Now we proceed to <em>complete</em> squares and factor each resulting perfect square trinomial in order to determine the coordinates of the center of the circle:

x^{2}+y^{2}-2\cdot x -10\cdot y +16 = 0

(x^{2}-2\cdot x +1)-1+(y^{2}-10\cdot y +25)-25 +16 = 0

(x-1)^{2}+(y-5)^{2}= 10

The center of the circle that circumscribe about DABC is (h,k) = (1, 5).

To learn more on circles, we kindly invite to check this verified question: brainly.com/question/11833983

5 0
3 years ago
( 13points)Help!!!
sammy [17]

Answer:

I believe your answer should be D. I am so sorry if it's wrong but it makes the most sense to my eyes. Hope it helps <3

7 0
3 years ago
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