Answer:
mass AsCl₃ in 8.2x10⁵ L = 99.2gAsCl₃
Step-by-step explanation:
Let's remember that 0.05 ppm (parts per million) would be write terms of mg/L. We have 0.05 mg/L, that is a concentration unit.
First of all we need to find the g/L of AsCl₃ present in water.
Now, we just need to multiply it by 8.2 x 10⁵ L to determine the mass of AsCl₃ present in that volume.
Finally we have:
.
Have a nice day!
Famous pa la playa pa curarte el some
The first step for solving this is to move the variable to the left side and then change its sign.
10 - 11d + 5d > - 4
Now move the constant to the right side and change its sign.
-11d + 5d > -4 - 10
Collect the terms with a
d variable.
-6d > -4 - 10
Calculate the difference on the right side.
-6d > -14
Lastly,, divide both sides of the inequality by -6 and flip the inequality sign to find your final answer.
d <
Let me know if you have any further questions.
:)
Answer: 1.5/2 and backwards-1.5/-2
Step-by-step explanation: rise over run
Answer:Its on 4
Step-by-step explanation:
