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geniusboy [140]
2 years ago
7

Can someone please help me with this ASAP? THANKS SO MUCH

Mathematics
1 answer:
Mice21 [21]2 years ago
4 0

Answer: 25

Step-by-step explanation:

B=3÷5×100

 =60

D=0.35×100

  =35

so,    B-D=60-35

              25

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Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

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Total number of cases = 15

Required probability is \frac{1}{15}.

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Total number of cases = 15

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c. At least one desktop:

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1. 1 desktop and 1 laptop:

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2. Both desktop:

Favorable cases = _4C_2=6

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Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
3 years ago
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