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Karo-lina-s [1.5K]
2 years ago
5

The table shows the amount of sugar needed to make lemonade. Are the quantities proportional? Explain which method you used and

how you used it to determine if they were proportionate or not.
Sugar (grams)

4

6

8

10

Servings

2

3

4

5
Mathematics
1 answer:
melomori [17]2 years ago
8 0

Answer:

Yes, the quantities are proportional.

Step-by-step explanation:

To determine whether they were proportional or not, I compared the ratio of grams of sugar to servings in each pair of data points. 4/2, 6/3, 8/4, and 10/5 were the four points. All of them can be simplified to 2/1, which tells us that each serving of sugar is 2 grams, no matter how many servings are counted. This means that the amount of sugar grows in direct proportion to the number of servings.

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Step-by-step explanation:

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2 years ago
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Dafna1 [17]
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5 0
3 years ago
F(x)= x+4; D: {-5, -3, 0, 4}
Vika [28.1K]

Step-by-step explanation:

-5+4=-1

-3+4=1

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6 0
3 years ago
Question:
aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

so

Let

z ----> the scale factor

\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}

The scale factor is equal to

z=\frac{CB}{C'B'}

substitute

z=\frac{4}{8}

simplify

z=\frac{1}{2}

Part B) What is the ratio of the areas (small to large)?

<em>Area of the small triangle</em>

A=\frac{1}{2}(2)(4)=4\ units^2

<em>Area of the large triangle</em>

A=\frac{1}{2}(4)(8)=16\ units^2

ratio of the areas (small to large)

ratio=\frac{4}{16}=\frac{1}{4}

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

4 0
3 years ago
Line h contains the points (3,0) and (0,4). which point lies on a line that is perpendicular to line h and passes through point
Iteru [2.4K]
(3,0)(0,4)
slope = (4 - 0) / (0 - 3) = -4/3
A perpendicular line will have a negative reciprocal slope. So our perpendicular line has a slope of 3/4

y = mx + b
slope(m) = 3/4
(-6,-5)....x = -6 and y = -5
now sub into the formula and find b, the y int
-5 = 3/4(-6) + b
-5 = -18/4 + b
-5 + 18/4 = b
-20/4 + 18/4 = b
-2/4 = b
so ur perpendicular line is : y = 3/4x - 2/4....or 3x - 4y = 2

and ur point (6,4) lies on the perpendicular line <===


6 0
3 years ago
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