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3 years ago

Solve for x.

Mathematics

2 answers:

kolezko [41]3 years ago

5 0

35(x-710)=–314

35x–24850=–314

35x–24850+24850=–314+24850

35x=24536

x= 24536/35

Answer: x= 24536/35

s2008m [1.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

710-35*x-(570-25*x)=0

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Later 7 students joined group 2 (41 students)and one student left to join group 1. (44 students) Now 20 students play trombone a

Anit [1.1K]

48 students in group 2

43 students in group 1

So in total there are 91 students

7 students play the trump

And 20 play the trombone

Therefore it is known that 27 students play those two instruments in total

Because of this, Subtract 27 from 91 to get the num of students who doesn't play those instruments.

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3 years ago

A tessellation has 2 pairs of congruent angles around the point of intersection. The measure of each of one pair of congruent an

Over [174]

9514 1404 393

Answer:

152°

Step-by-step explanation:

If two pairs of congruent angles total 360°, then the different angles must total 180°. The other angle measure is 180° -28° = 152°.

The measure of each angle in the other congruent pair is 152°.

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3 years ago

Hi can someone help me out with this problem.

elena-s [515]

Answer:

third side = 9

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let the third side be x, then

x² + 40² = 41², that is

x² + 1600 = 1681 ( subtract 1600 from both sides )

x² = 81 ( take the square root of both sides )

x = $\sqrt{81}$ = 9

The third side is 9

3 0

3 years ago

Read 2 more answers

factorise completely (x plus 2) Square - (x - 4) Square and hence find then value of 1000 Square minus 992 Square

tekilochka [14]

Answer:

$x^2+3x+8$

$15936$

Step-by-step explanation:

$\left(x+2\right)^2-\left(x-4\right)$

$\left(x+2\right)\left(x+2\right)-\left(x-4\right)$

$x^2+2x+2x+4-(x-4)$

$x^2+4x+4-\left(x-4\right)$

$x^2+4x+4-x+4$

$x^2+3x+8$

$1000^2-992^2$

$1000000-984064$

$15936$

3 0

3 years ago

Starting at 6 a.m. every morning, Matilda receives text messages on her cell phone from her mother, her best friend, and her bro

Dafna1 [17]

Answer:

a) 0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

b) $1.6 \times 10^{-9}$ probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

A) Find the probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

Two from the best friend:

Her best friend sends a message once every 10 minutes.

From 6 to 7:30, there is an hour and a half, that is, 90 minutes, so the mean for her best friend is $\mu = \frac{90}{10} = 9$

Two messages is P(X = 2). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-9}*9^{2}}{(2)!} = 0.0050$

Two from the mother:

Message every hour = 60 minutes. So $\mu = \frac{90}{60} = 1.5$ . This is P(X = 2).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-1.5}*1.5^{2}}{(2)!} = 0.2510$

Two of her best friend and two of her mother:

Independent events, so the probability of both happening is the multiplication of their separate probabilities.

$p = 0.005*0.251 = 0.0013$

0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

B) With a chance of 75% a text message contains a typo independent of the sender. Find the probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

In 3 hours, she is expected to receive:

3*60/10 = 18 messages from her best friend.

3*60/60 = 3 messages from her mother.

3*60/30 = 6 messages from her brother.

In total, 27 messages.

75% probability of a typo, so $\mu = 0.75*27 = 20.25$

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20.25}*20.25^{0}}{(0)!} = 1.6 \times 10^{-9}$

$1.6 \times 10^{-9}$ probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

8 0

3 years ago