First we will find the 11th term
an = a1 + (n-1) * d
a11 = 12 + (11 - 1) * 5
a11 = 12 + 10 * 5
a11 = 12 + 50
a11 = 62
now we use the sum formula...
Sn = (n (a1 + an)) / 2
S11 = (11 (12 + 62)) / 2
S11 = (11 (74)) / 2
S11 = 814/2
S11 = 407
This involvea factoring the polynomial into binomials and solving.
So make it (3x+1)(x-7)
X equals 7 and -1/3
<u>Given</u>:
Let the two numbers be x and y.
Two numbers multiply to be -7 and add to be -6.
This can be written in equation as,
and

<u>Value of the two numbers:</u>
Let us determine the value of the two numbers using substitution method.
Substituting
in the equation
, we get;

Simplifying, we get;




Thus, the values of x are x = 1,-7
When x = 1 , the equation
becomes 
When x = -7, the equation
becomes 
Therefore, the two numbers are 1 and -7
Answer:

Step-by-step explanation:
<u>Firstly, we'll do prime factorization of these numbers.</u>
70 = 2 × 5 × 7
112 = 2 × 2 × 2 × 2 × 7
<u>So, The Greatest Common Factor can be written as:</u>
GCF = 2 × 7 <u>[Since Only one 2 and one 7 is common]</u>
<u></u>
Hope this helped!
<h2>~AnonymousHelper1807</h2>
Vertex=(-1,0)
x^2-2x-1
y=− ( x + 1 )^2 + 0
Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.
Find the vertex (h,k) = (-1,0)