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vekshin1
3 years ago
11

Evaluate the expression when x = -3 -5x -15 Show your work

Mathematics
1 answer:
Kisachek [45]3 years ago
7 0

-5x - 15

-5(-3) - 15

15 - 15

0

Hope this helps! :)

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Can you please do 2 and 3
Masja [62]

Answers:

<h2>2. 17.5</h2><h2>3a. 6</h2><h2>3b. greater</h2><h2>3c. add 1 to it</h2>

Step-by-step explanation:

When rounding, look at the digit that is ls to the right beside the digit in the place value to round to. If the number is greater than or equal to 5, round the digit in the place value to round to up one. If it is less than 5, do not. Let's look at some examples.

EXAMPLE 1:

23.123 round to the nearest tenth.

23.<u>1</u>23 tenths place is underlined

Digit after tenths is bold. If greater than or equal to 5, round underlined digit up. If less than 5, don't change underlined digit.

The bold number is a 2, which is less than 5, so the underlined number doesn't change.

ANSWER TO EXAMPLE 1: 23.1

EXAMPLE 2:

57.54 round to the nearest whole number

5<u>7</u>.54 Nearest whole place value is underlined

Digit after underlined digit is bold. If greater than or equal to 5, round underlined digit up one. If bold digit is less than 5, don't change the underlined digit.

The bold number is a 5, which equals 5, so the underlined number increases by 1.

ANSWER TO EXAMPLE 2: 58

Now, let's examine yours, now that we know how to round

17.46 round to the nearest tenth

17.<u>4</u>6 tenths place is underlined

Digit after tenths is bold. If greater than or equal to 5, round underlined digit up by one. If bold digit is less than 5, don't change the underlined digit.

The bold number is a 6, which is greater than 5, so the underlined number increases by 1.

ANSWER TO QUESTION: 17.5

Hope this helped :)

<em>PLEASE MARK BRAINLIEST</em>

8 0
3 years ago
Someone please explain how to do this problem? :)<br><br> Factor completely 2c5 + 44c4 + 242c3.
frez [133]
<span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span>=<span><span><span>2<span>c3</span></span><span>(<span>c+11</span>)</span></span><span>(<span>c+11</span><span>)</span></span></span></span>
8 0
3 years ago
Read 2 more answers
Super easy... #10-12. LOOK AT PICTURE! URGENT!
alisha [4.7K]
10
sum is add
cube is to the 3rd powr
19+x³


11.
product means multiply
3 times y is no more than (equal to or less than ) 21
3y≤21
no need to solve

12. 2 times difference is 10
difference is subtract

2(z-12)=10
7 0
3 years ago
$1500 computer 7% tax
lina2011 [118]

Answer:

$1605

Step-by-step explanation:

since 100% = 1, just <em>multiply</em> 1 <em>(100% aka given price)</em> and 0.07 <em>(7%) </em>by 1500:

1500(1.07)

<em>= 1605</em>

the computer with tax added would be $1605

3 0
3 years ago
Read 2 more answers
Explain the rule in solving inequalities with a negative coefficient.
dimulka [17.4K]

Answer:

  the comparison must be reversed when multiplying by a negative

Step-by-step explanation:

The rules of equality apply to solving inequalities, with the exception that multiplication or division by a negative number reverses the sense of the comparison:

  -x > 1

  x < -1 . . . . . multiply both sides by -1

____

Effectively, multiplication (or division) by a negative number is equivalent to reflection across the origin. Things that were ordered left/right (on the number line) are ordered right/left after such a reflection:

  -2 < -1

  1 < 2

_____

<em>Additional comment</em>

Application of any function requires that you pay attention to ordering. Some functions naturally reverse the order; others do so only on specific domains.

Consider f(x) = 1/x.

  1 < 2

  f(1) > f(2) . . . . because the slope of the f(x) function is negative everywhere.

__

<em>In the first and second quadrants</em>, the cosine function also reverses order.

  20° > 10°

  cos(20°) < cos(10°)

__

Probably the most commonly encountered function used with inequalities is the absolute value function.

  |x-3| > 2

This function has one domain where the slope is negative, and another domain where the slope is positive.

  For x < 3, the function negates its argument, so we have ...

     -(x -3) > 2

     -x +3 > 2

     -x > -1

     x < 1 . . . . . everywhere consistent with x < 3

  For x ≥ 3, the function does nothing, so we have ...

     x -3 > 2

     x > 5

  The solution to this absolute value inequality is (x < 1) ∪ (x > 5).

__

You can also resolve negative coefficients by adding the opposite. Addition and subtraction never require any change to the comparison operator.

  -x > 1

  0 > x +1 . . . . x is added

  -1 > x . . . . . . -1 is added

7 0
3 years ago
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