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3 years ago

Use pascals triangle to expand the binomial (d-3)^6

Mathematics

1 answer:

TiliK225 [7]3 years ago

8 0

Answer:

d^6 - 18d^5 + 135d^4 - 540d^3 + 1215d^2 - 1458d + 729

Step-by-step explanation:

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Please help! The radius of a sphere is claimed to be 3.0 inches, correct to within 0.01 inch. Use linear approximation to estima

Vilka [71]

Answer:

0,36π inches³ or simply 1.13 inches³

Step-by-step explanation:

In this case, first, we need to calculate the volume of the sphere with the formula:

V = 4πr³/3

Replacing the data we have:

V = 4π(3)³/3

V = 36 in³

Now that we have the volume we need to calculate the resulting error. In this case, using linear approximation we have to use the derivates of V and r, so we have the following:

If V = 4πr³/3

Then the derivate of V (dV) would be:

dV = 4π*3*r²/3 dr

Where dr is the error of radius so:

dV = 4π*r² dr

Solving for dV:

dV = 4*3.14*(3)²*(0.01)

dV = 1.13 in³

So at the end, we just report the volume of the sphere as

V = 36 ± 1 in³

dV =

3 0

3 years ago

HELP ME FOR NUMBER 1 & 2

Novay_Z [31]

It would be 6x5 squared-5x4+8
150-20+8=138

3 0

3 years ago

Identify the expression equivalent to 4(x+x+y)-2x+8+4 by substituting x=1 and x=2

Shtirlitz [24]

4(1+1+2)-2(1)+8+4 you would just plug it in for x and y. And then solve the equation.

4 0

4 years ago

URGRENNTTT PLSS HELPP 50 POINTSS!!!!! Students were asked to simplify the expression cotangent theta plus tangent theta over cot

Naddika [18.5K]

The student that simplified the expression incorrectly is student 2

<h3>How to determine the incorrect result?</h3>

The steps are given as:

$\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)}$

Student 1:

Step 1: $\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}$
Step 2: $1 + \frac{\tan(\theta)}{\cot(\theta)}$
Step 3: 1 + tan²(Ф)
Step 4: sec²(Ф)

Student 2:

Step 1: $\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}$
Step 2: $\frac{1 + \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}$
Step 3: sec²(Ф)/tan²(Ф)
Step 4: csc²(Ф)

As a general trigonometry rule;

$\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)} = \sec^2(\theta)$

This means that student 1 is correct, while student 2 is not

The first error in student 2's workings is in step 2, where we have:

$\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)} = \frac{1 + \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}$

The above expression is not justified and cannot be proved by any trigonometry rule

Since the step 2 is incorrect, the other steps cannot be used.

Hence, the student that simplified the expression incorrectly is student 2

Read more about trigonometric expressions at:

brainly.com/question/8120556

#SPJ1

5 0

2 years ago

Ricard lost 6 golf balls while playing yesterday. He bought a box of 12 golf balls ,then lost 4 on the course today . He now has

viktelen [127]

16, first you need to add on the four he lost to the 18 he ended with.

4 0

4 years ago