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2 years ago

How many times larger is the 8 in 184.36 than 9,027.83

Mathematics

1 answer:

Sunny_sXe [5.5K]2 years ago

4 0

Answer: Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.

Step-by-step explanation:

First we can find out the place value,

Then we can write,

Define Place value :

Place value is the basis of our entire number system. This is the system in which the position of a digit in a number determines its value. The number 42,316 is different from 61,432 because the digits are in different positions.

[or]

Place value of a digit can be defined as the position of the particular digit in a given number.

For Example :

The place value of 7 in 1870 is 70

Given the data,

First we use digit is : 184.36

Second we use digit is : 9027.83

Place value of 8 in First digit is ⇒ 184.36 is 80

Place value of 8 in Second digit is ⇒ 9027.83 is 0. 8

We can solve the Ratio is :

Ratio = 80/ 0.8

Ratio = 100 times

Therefore,

Thus, the number with the larger value of 8 is 184.36 and it is 100 times larger.

Learn more about event correlation here: brainly.com/question/17103145

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So have the sequence: $\frac{1}{5} , \frac{2}{15} , \frac{4}{45} , \frac{8}{135} , \frac{16}{145} ,...$
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$a_{n-1}$ is the previous term in the sequence
In other words we are going to divide the current term by the previous term a few times, and we will to check if that ratio is the same:

For $a_{n}= \frac{2}{15}$ and $a_{n-1}= \frac{1}{5}$ :
$r= \frac{ \frac{2}{15} }{ \frac{1}{5} }$
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For $a_{n}= \frac{4}{45}$ and $a_{n-1}= \frac{2}{15}$ :
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