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3 years ago

Which congruence theorem can be used to prove WXS and YZS?

Mathematics

1 answer:

mariarad [96]3 years ago

3 0

I am going to make what is hopefully not an incorrect assumption and say that since the segmentXSZ is black and the other lines are blue, that XS is congruent to ZS. If that be the case we have a side in each triangle that is congruent to each other and an angle that is marked as congruent. Angles XSW and ZSY are vertical angles. By definition, vertical angles are congruent. In each triangle, then, we have an angle, a side and an angle which gives us the congruency postulate ASA.

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, list the first five terms of each sequence. f(n + 1) = −2f(n) + 8 and f(1) = 1 for n ≥ 1

svet-max [94.6K]

Answer: 1, 7, 1, 7, 1.

Step-by-step explanation:

The given function : $f(n+1)=-2f(n)+8$ and f(1) = 1 for n ≥ 1

We put value of n=1,2,3,4 , we get

For n=1 , $f(2)=f(1+1)=-2f(1)+8=-1(1)+8=-1+8=7$

For n=2 , $f(3)=f(2+1)=-2f(2)+8=-1(7)+8=1$

For n=3 , $f(4)=f(3+1)=-2f(3)+8=-1(1)+8=7$

For n=4 , $f(5)=f(4+1)=-2f(4)+8=-1(7)+8=1$

Hence, the first five terms of the given sequence are 1, 7, 1, 7, 1.

7 0

3 years ago

(7x+5)(2x3-4x2+9x-3)

Zanzabum

I believe the answer is 3x(3x + 2)

Step-by-step explanation:

4 0

3 years ago

A bag contains 26 tiles, each with a different letter of the alphabet written on it. You choose 3 tiles from the bag without loo

blagie [28]

Answer:

1/26

Step-by-step explanation:

Total no. of tiles = 26

In each tile , a different alphabet is written.

And we need 3 tiles (in which A , B & C are written in it) in one try.

So the probability of choosing tiles with letters A , B & C ( in one try ) = 1/26

4 0

2 years ago

Can anybody help me please

GREYUIT [131]

Question 7: Option 1: x = 33.5°

Question 8: Option 3: x = 14.0°

Step-by-step explanation:

Question 7:

In the given figure, the value of perpendicular and hypotenuse is given, so we have to use any trigonometric ratio to find the value of angle as the given triangle is a right-angled triangle

So,

Perpendicular = P = 32

Hypotenuse = H = 58

So,

$sin\ x = \frac{P}{H}\\sin\ x = \frac{32}{58}\\sin\ x = 0.5517\\x = sin^{-1} ( 0.5517)\\x =33.48$

Rounding off to nearest tenth

x = 33.5°

Question 8:

In the given figure, the value of Base and Perpendicular is given, we will use tangent trigonometric ratio to find the value of x

So,

Perpendicular = P = 5

Base = B = 20

So,

$tan\ x = \frac{P}{B}\\tan\ x = \frac{5}{20}\\tan\ x = 0.25\\x = tan^{-1} (0.25)\\x = 14.036$

Rounding off to nearest tenth

x = 14.0°

Keywords: Right-angled triangle, trigonometric ratios

Learn more about trigonometric ratios at:

#LearnwithBrainly

8 0

3 years ago

Alisa says it is easier to compare the numbers in set A 45,760-1,025,680 than set B492,111-409,867

Marysya12 [62]

What is the question?

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3 years ago