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nordsb [41]
3 years ago
15

Which congruence theorem can be used to prove WXS and YZS?

Mathematics
1 answer:
mariarad [96]3 years ago
3 0

I am going to make what is hopefully not an incorrect assumption and say that since the segmentXSZ is black and the other lines are blue, that XS is congruent to ZS. If that be the case we have a side in each triangle that is congruent to each other and an angle that is marked as congruent. Angles XSW and ZSY are vertical angles. By definition, vertical angles are congruent. In each triangle, then, we have an angle, a side and an angle which gives us the congruency postulate ASA.

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Question 6 (2 points)
Orlov [11]

Answer:

Blank 1: (-7,0)

Blank 2: (-1,0)

Step-by-step explanation:

Plug x=0 into the equation and solve the resulting equation y=7 for y

Plug y=0 into the equation and solve the resulting equation 0=(x+1)(x+7) for x

6 0
3 years ago
Jay ate 2/3 of a pizza. Dan ate 4 times the amount of jay ate . How much did dan eat
erica [24]

Answer:

Dan eat 2\frac{2}{3} pizzas

Step-by-step explanation:

Let

x-----> amount of pizza Jay ate

y-----> amount of pizza Dan ate

we know that

x=\frac{2}{3} ----> equation A

y=4x -----> equation B

substitute equation A in the equation B and solve for y

y=4(\frac{2}{3})=\frac{8}{3}

Convert to mixed number

\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}

8 0
3 years ago
Help pls I’ll give 50 points ! If right math ppl
Georgia [21]

f(x)=-3x

Substitute x = 5 in the equation.

f(5)=-3(5)\\f(5)=-15

Therefore, the answer is -15 or last choice when x = 5.

3 0
3 years ago
Read 2 more answers
Which monomial function has a minimum value? y=5x^10 y=-4x^11 y=-x^12 y=6x^7
strojnjashka [21]
<span>y=-x^12  has the minimum value.</span>
8 0
3 years ago
Read 2 more answers
Find the missing side lengths and leave the radicals in the simplest form.
yKpoI14uk [10]

Answer:

y=\frac{9\sqrt{2} }{2} and x=9

Step-by-step explanation:

We can see that the triangle is a special triangle or isosceles triangle meaning that two angles/ two sides are the same.

y=\frac{9\sqrt{2} }{2}

To solve for x use Pythagorean Theorem.

a^2 + b^2 = c^2.

\frac{9\sqrt{2} }{2} +\frac{9\sqrt{2} }{2}=x^2\\\\\frac{81}{2} +\frac{81}{2} =x^2\\\\\frac{162}{2} =x^2\\\\x=\sqrt{\frac{162}{2} } =\sqrt{81} =9\\\\x=9

4 0
2 years ago
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