Answer:
<h2><em><u>8</u></em></h2>
Step-by-step explanation:
As,
1/4 = (1×2)/(4×2) = 4/8
4/8 = (4×1)/(8×1) = 4/8
In both case,
The denominator 8 is least common multiple
The way I remember domain(the distance where x is shown) and range(the distance where y is shown) is that it lines up with an ordered pair. It sounds wrong to say range and domain, just like it sounds wrong to say y,x.
the answer for this would be [0,11]
6 11/14 would be the correct answer to your math problem!
Answer:
x<6/5, x>14/5
Step-by-step explanation:
Steps
$5\left|x-2\right|+4>8$
$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$
$5\left|x-2\right|+4-4>8-4$
$\mathrm{Simplify}$
$5\left|x-2\right|>4$
$\mathrm{Divide\:both\:sides\:by\:}5$
$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$
$\mathrm{Simplify}$
$\left|x-2\right|>\frac{4}{5}$
$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$
$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$
Show Steps
$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$
Show Steps
$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$
$\mathrm{Combine\:the\:intervals}$
$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$
This is how u would find horizontal and vertical asymptotes
