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ozzi
3 years ago
13

4 sinA + 5 sinA what is the answer of it​

Mathematics
1 answer:
iragen [17]3 years ago
4 0

Answer:

9 sinA

Step-by-step explanation:

Adding them is all you can do to simplify.

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Free brainist for right anwsers
geniusboy [140]

Answer:

i need the points sorry!

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Angela is shopping for pet supplies and needs to buy a kennel and several toys. At Paws R Us, she would pay $50.75 for the kenne
zhenek [66]

Answer: t>6

Step-by-step explanation:

Amount to pay = Cost of kennel + (Cost per toy )x (Number of toys)

Let t = the number of pet toys Angela would need to buy for Paws R Us to be the cheaper option.​

Given, At Paws R Us, she would pay $50.75 for the kennel and $3.75 for each pet toy.

Amount to pay =  $(50.75 + 3.75t)

At Truth or Tail, she would pay $43.25 for the kennel and $5 for each pet toy.

Amount to pay =  $(43.25 + 5t)

According to the question , we have

50.75 + 3.75t < 43.25 + 5t

Subtract 3.75t from both sides

50.75+ 3.75t -3.75t   < 43.25 + 5t -3.75t

⇒ 50.75< 43.25 +1.25 t

Subtract  43.25 from both sides, we get

50.75 - 43.25 < 1.25 t

⇒  7.5< 1.25 t

Divide both sides by 1.25 we get

⇒   6<t

Hence, the required inequality to represent t, the number of pet toys Angela would need to buy for Paws R Us to be the cheaper option:

t>6 .

5 0
3 years ago
Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

5 0
3 years ago
What is the value of 40/z, when z = 10? <br><br>I WILL GIBE BRAINLY POINTS
Mamont248 [21]

Replace x with 10 and simplify the fraction.

40/10 = 4/1 = 4

The answer is 4

5 0
2 years ago
A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

8 0
3 years ago
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