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2 years ago

Nov 05, What is an equation of the line that passes through the points (3,-6) and (-7, - 6)?

2 answers:

6 0

Hmmmmm, are you sure you have no other information? does it tell you if it’s linear or quadratic or cubic or quartic? what math are you doing right now?

krok68 [10]2 years ago

3 0

Answer:

If you want to show no work, the answer is y = -6

If you are required to show work:

The slope between the two points is(-6 - -6) / (-7 - 3) = 0/-10 = 0 and the y intercept has to be -6 so according to the slope intercept form of a line the equation would be y = 0x + (-6) or just y = -6

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Answer:

$(B)r=\dfrac{85}{12}$

Step-by-step explanation:

Given a circle centre J

Let the radius of the circle =r

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From the diagram attached

LX=6
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Theorem: The angle between a tangent and a radius is 90 degrees.

By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.

Using Pythagoras Theorem:

$(6+r)^2=r^2+11^2\\(6+r)(6+r)=r^2+121\\36+6r+6r+r^2=r^2+121\\12r=121-36\\12r=85\\r=\dfrac{85}{12}$

The length of the radius, $r=\dfrac{85}{12}$

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