Each one counts as 3 so you=9hours and Friend=3hours 9+3=13 hours
(1/2) * x^3 + 3.4y when X = 2 and Y = 5.
= (1/2) * (2^3) * 3.4(5)
= (1/2) * 8 * 17
= (1/2) * 136
= 136/2
= 68.
Answer:
Cost of one rocket = $1.5
Step-by-step explanation:
Given:
6 rockets and 11 bombs cost = $36.50
14 rockets and 8 bombs cost = $41
Find:
Cost of one rocket
Computation:
Cost of one rocket = x
Cost of one bomb = y
So,
6x + 11y = 36.50.....eq1
14x + 8y = 41......eq2
From eq1
y = [36.50 - 6x]/11
From eq2
14x + 8y = 41
14x + 8[36.50 - 6x]/11 = 41
x = 1.5
Cost of one rocket = $1.5
