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2 years ago

6 remainder 1 as a fraction

Mathematics

1 answer:

natka813 [3]2 years ago

6 0

Six and one sixth or 6 1/6

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Name the postulate, Definition or Property below

klasskru [66]

Ans_ It is Sandwich Theorem..

3 0

3 years ago

Anybody, please answer this for me. I'm not good at mathematics

Lostsunrise [7]

Well, its kind of obivious that 2x + 4 stands out, but I think you are asking why. Whereas all other lines shown are vertical or horizontal, 2x+4 is diagonal.

3 0

3 years ago

2) The 114 students in the ninth grade at Mathville High are going on a field trip to the science

9966 [12]

Answer:

4 buses

Step-by-step explanation:

40b=114+114/10

40b=114+11.4

40b=125.4

b=3.135

The answer is 4 because you have to round up to get the remaining people.

5 0

3 years ago

Use the Quadratic Formula to solve the equation 4x^2−7=4x.

tino4ka555 [31]

Answer:

$\large\boxed{x=\dfrac{1}{2}-\sqrt2\ or\ x=\dfrac{1}{2}+\sqrt2}$

Step-by-step explanation:

$\text{The quadratic formula of}\ ax^2+bx+c=0:\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\text{We have:}\\\\4x^2-7=4x\qquad\text{subtract}\ 4x\ \text{from both sides}\\\\4x^2-4x-7=0\\\\a=4,\ b=-4,\ c=-7\\\\b^2-4ac=(-4)^2-4(4)(-7)=16+112=128\\\\\sqrt{b^2-4ac}=\sqrt{128}=\sqrt{64\cdot2}=\sqrt{64}\cdot\sqrt2=8\sqrt2\\\\x=\dfrac{-(-4)\pm8\sqrt2}{(2)(4)}=\dfrac{4\pm8\sqrt2}{8}\qquad\text{simplify by 4}\\\\x=\dfrac{1\pm2\sqrt2}{2}\to x=\dfrac{1}{2}\pm\sqrt2$

6 0

3 years ago

Consider the following 8 numbers, where one labelled X is unknown.

Effectus [21]

Answer:

$55,-3$

Step-by-step explanation:

$We\ are\ given\ that,\\There\ are\ eight\ numbers\ in\ the\ data :\\17,18,24,x,44,48,42,4\\Where\ the\ value\ of\ x\ is\ what\ we\ need\ to\ find.\\Range\ of\ the\ data=51\\Hence,\\We\ know\ that\ the\ range\ is\ the\ difference\\ between\ the\ highest\ observation\ and\ the\ lowest\ observation\ in\ the\ data.\\We\ may\ know\ see\ two\ cases\ of\ evaluating\ x\ when:\\1. x\ is\ the\ highest\ observation\ in\ the\ data\ or\ x>48.\\Highest\ observation\ =x\\Lowest\ observation=4\\Hence,\\$

$As\ range=51,\\x-4=51\\x=51+4\ [Adding\ 4\ on\ both\ the\ sides]\\x=55 \\2. x\ is\ the\ lowest\ observation\ or\ x$

7 0

3 years ago