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Anni [7]
2 years ago
13

Mrs. Rush puts $300 in a bank account that earns 5% interest every year. How much will be in the bank after 3 years? (make sure

you include the $ sign and round your answers to two decimal places
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
3 0

Answer:

$945 no cents so no need to round the recimals

Step-by-step explanation:

$300 times the 5% is $15 dollars in interest

so in three years it would be an additional $45 dollars

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How do you complete <br>-6/5k=12
Inessa [10]
Here, I'll help you a little
rewrite the equation as -6k/5 = 12
multiply both sides by 5
-6k=60
divide both sides by -6 to isolate k
k = -10 

Hope this helps :)
6 0
2 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
2 years ago
Need help on this question for math
KATRIN_1 [288]

Answer:

y=-7

Step-by-step explanation:

hope that will help you

8 0
3 years ago
Subtract. Write your answer as a mixed number in simplest form.<br><br> 8 1/4 + 4 5/6
Tasya [4]

Answer:

13 1/12

Step-by-step explanation:

6 0
3 years ago
Through her bike 6 miles from her house to the library and then another two and 250 miles to her friend Milo's house and Carson'
Katarina [22]
25 ok i think that
 ok byeeeeee
4 0
3 years ago
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