Answer:
x = 7.8
Step-by-step explanation:
a^2 + b^2 = c^2
4^2 + 2^2 = c^2
16 + 4 = c^2
c^2 = 20
c = 4.5
a^2 + b^2 = c^2
a^2 + 4.5^2 = 9^2
a^2 + 20.25 = 81
a^2 = 81 - 20.25
a^2 = 60.75
a = 7.8
Let me help you!
Ok, so before I give you the answer, which is very simple, I will first show you how to answer questions like this in the future.
In the variable declaration, the array "numbers[]" has been declared as an integer. The values of the array "numbers[]" are: <span>83, 62, 77, 97, 88; respectively, the values are equivalent to: 0, 1, 2, 3, 4 which makes the range of array "numbers[]": 5.
To make it clearer:
</span>numbers[0] = 83
numbers[1] = 62
numbers[2] = 77
numbers[3] = 97 <---- This is what we are looking for!
numbers[4] = 88
*** By the way, when counting the range, we don't start at 1, we start at 0. That's why even if the range is 5, the last value is 4.
Therefore, the answer is: 3 or numbers[3].
A. Using the straight-line depreciation method, we can
calculate for the depreciation using the formula:
d = (P – S) / n
Where,
P = present value
S = salvage value
n = number of life years
Substituting the given values:
d = ($465,000 - $45,000) / 15
d = $28,000
The depreciation for the first year was $28,000 and the
book value is $437,000.
B. Calculating for the book value at the end of eight
year:
BV (8) = $465,000 – 8 * $28,000
BV (8) = $241,000
<span>Since the equipment was sold at only $235,000 therefore
there was a loss of $6,000.</span>
<span>C. Chart of accounts is needed.</span>
D because you are finding the difference
Answer:
use photo math plz mark me brainlisist
Step-by-step explanation:
