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3 years ago

Solve for c when a=11+4b-4c

2 answers:

4 0

Remember, you can do anything to an equation as long as yo do it to both sides
minus 11 bothsides
a-11=4b-4c
minus 4b both sides
a-11-4b=-4c
divide both sides by 4
$\frac{a-11-4b}{4}=-c$
multiply both sides by -1
$\frac{-a+11+4b}{4}=c$
$c=\frac{-a+11+4b}{4}$
$c=\frac{4b-1+11}{4}$

Marina86 [1]3 years ago

3 0

11+4=15-4=11
So a=11 I think so am not sure

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Herman and Jackie are saving money to pay for college. Herman currently has $15,000 and is working hard to save $1000 per month.

Mashutka [201]

Answer:

Part 1) $10\ months$

Part 2) $\$25,000$

Step-by-step explanation:

Let

y ----> the total amount of savings

x ----> the number of months

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

<em>Herman</em>

The slope is equal to $m=\$1,000\ per\ month$

The y-intercept is $b=\$15,000$

substitute

$y=1,000x+15,000$ ----> equation A

<em>Jackie</em>

The slope is equal to $m=\$1,300\ per\ month$

The y-intercept is $b=\$12,000$

substitute

$y=1,300x+12,000$ ----> equation B

Part 1) In how many months will they have the same amount of savings?

equate equation A and equation B

$1,300x+12,000=1,000x+15,000$

solve for x

$1,300x-1,000x=15,000-12,000$

$300x=3,000$

$x=10\ months$

Part 2) How much will each of them have saved?

substitute the value of x=10 months in any of the equations

equation A

$y=1,000(10)+15,000=\$25,000$

equation B

$y=1,300(10)+12,000=\$25,000$

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3 years ago

Is y=10-2/x a liner or nonlinear equation?

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Answer:

non-linear

Step-by-step explanation:

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shusha [124]

Solve for z:
5 (z + 6) - 2 = 9 z

5 (z + 6) = 5 z + 30:
5 z + 30 - 2 = 9 z

Add like terms. 30 - 2 = 28:
5 z + 28 = 9 z

Subtract 9 z from both sides:
(5 z - 9 z) + 28 = 9 z - 9 z

5 z - 9 z = -4 z:
-4 z + 28 = 9 z - 9 z

9 z - 9 z = 0:
28 - 4 z = 0

Subtract 28 from both sides:
(28 - 28) - 4 z = -28

28 - 28 = 0:
-4 z = -28

Divide both sides of -4 z = -28 by -4:
(-4 z)/(-4) = (-28)/(-4)

(-4)/(-4) = 1:
z = (-28)/(-4)

The gcd of 28 and -4 is 4, so (-28)/(-4) = (-(4×7))/(4 (-1)) = 4/4×(-7)/(-1) = (-7)/(-1):
z = (-7)/(-1)

(-7)/(-1) = (-1)/(-1)×7 = 7:
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