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m_a_m_a [10]
3 years ago
15

Can someone help me find the answer for M>5

Mathematics
2 answers:
Sauron [17]3 years ago
5 0
142 ————————————————
Grace [21]3 years ago
4 0
The answer is 142. 

Hope this helped.<3

Have a great day!!
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Muad can lift 129.6 pounds and Samara can lift 135.25 pounds. How much more weight can Samara lift?
notka56 [123]

Answer:5.29 pounds

Step-by-step explanation:

135.25 -129.6

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3 years ago
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What is the area of a semi circle that has a diameter of 1 1/2?
SVEN [57.7K]

Answer:

A=0.8836

Step-by-step explanation:

Area of circle:

\pi r^2

By using the area of a circle, we can get the area of a semicircle:

\frac{\pi r^2}{2}

Let's convert the mixed fraction to an improper fraction and then a decimal:

1\frac{1}{2} = \frac{3}{2} = 1.5

Now, we solved for the diameter, to get the radius, we need to divide the diameter by 2:

\frac{1.5}{2} =0.75

Now we have the radius, so we can plug in our values and find the area:

\frac{\pi0.75^2}{2} = 0.88357293

A=0.88357293

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3 years ago
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Place the following linear equation in slope intercept form: 6x - 4y = 9
geniusboy [140]

Answer:

y = 3/2 x - 9/4

Step-by-step explanation:

bring all the y's to one side.

4y = 6x-9

divide by 4 to isolate the y

y = 6/4x - 9/4

simplify

y = 3/2 x - 9/4

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3 years ago
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Find the mean of this data set: {– 78, -12, 3, – 44}
blagie [28]

Answer:

<u>Answer</u><u>:</u><u> </u><u>A</u><u>.</u><u> </u><u>-</u><u>3</u><u>2</u><u>.</u><u>7</u><u>5</u>

\dashrightarrow{ \tt{mean =  \frac{ \sum f(n)}{n} }} \\

• f(n) are the values of the set

• n is the number of items

\dashrightarrow \: { \tt{mean =  \frac{ - 78 + ( - 12) + 3 + ( - 44)}{4} }} \\  \\  \dashrightarrow \: { \tt{ \frac{ - 131}{4} }} \\  \\  \dashrightarrow \: { \boxed{ \tt{mean =  - 32.75}}}

5 0
3 years ago
Suppose that 350 cervical cancer cases were identified and a random sample of women of the same age range who were admitted to t
11111nata11111 [884]

Answer:

a)The ratio of the odds of exposure among cases and controls equal to 5.3

Step-by-step explanation:

Correct option is:

The ratio of the odds of exposure among cases and controls equal to 5.3

Solution:

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Odds for controls=0.63/0.37=1.703

Odds ratio=9/1.703=5.3

Hence the correct option is  a)The ratio of the odds of exposure among cases and controls equal to 5.3

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