Hello :
<span>f(x)=x²+4x-5
</span><span>The axis of symmetry for a function in the form f(x)=x^2+4x-5 is x=-2 :
</span>f(x) = (x+2)² + b
f(x) x²+4x+4+b= x² +4x-5
4+b= -5
b = -9
the vertex is : (2 , -9)
Answer:
x = 8
Step-by-step explanation:
9(x - 4) = 2(x + 10)
9x - 36 = 2x + 20
7x = 56
x = 8
Please mark as brainliest :)
The answer is... Five less than C
Do you have the specific point??
Remember, if 2 lines are perpendicular, their slopes are opposite reciprocals. So if one line has a slope of 4, the other line should have a slope of -1/4.
Hopefully your equation is in y=mx+b form. If so,
make sure you know slope (m) and the y-intercept. After this is done, plug in the points from p for y and x, and make sure to turn m into -1/m. Solve for b, and your new equation should be y=(new slope)x+(new y-intercept)
Total = Principal * e^(rate*years)
where "e" is the mathematical constant 2.71828182828459
Total = 1,600 * e(.046*4)
Total = 1,600 * 2.71828182828459^(.184)
Total = 1,600 *
<span>
<span>
<span>
1.2020158231
</span>
</span>
</span>
Total =
<span>
<span>
<span>
1,923.23</span></span>
</span>
Source:
http://www.1728.org/rate2.htm