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velikii [3]
3 years ago
6

Joyce is buying supplies at the school bookstore. A pencil costs $0.25, a notebook costs $1.75, and a piece

Mathematics
2 answers:
makvit [3.9K]3 years ago
4 0

Let Pencils be P

Let notebooks be N

Let graph paper be G

Let cost be C

(Always write a let statement before you write and algebraic equation)

C= (Px0.25)+(Nx1.75)+(Gx0.05)

White raven [17]3 years ago
3 0

Answer:

C = 0.25x +1.75y +0.05z in dollars

Step-by-step explanation:

Let 'x' be the number of pencils, 'y' be the number of notebooks, and 'z' be the  number of graph papers bought. Then the total cost 'C' in dollars should be:

C = 0.25x +1.75y +0.05z

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PLEASE HELP!! A classmate wrote the set notation for the values of the domain of a function {−5, −4, −3, −2, −1, 0} as {x | −5 ≤
vfiekz [6]
<h3>Answer: Choice B</h3>

The set notation includes all values from -5 to 0, but the domain only includes the integer values

eg: something like -1.2 is in the second set, but it is not in the set {-5,-4,-3,-2,-1}

==========================================================

Further explanation:

Let's go through the answer choices one by one

  • A. This is false because 0 does not come before -5, but instead -5 is listed first. The order -5,-4,-3,-2,-1,0 is correct meaning that -5 \le x \le 0 is the correct order as well.
  • B. This is true. A value like x = -1.2 is in the set \left\{x| -5 \le x \le 0\right\} since -1.2 is between -5 and 0; but -1.2 is not in the set {-5, -4, -3, -2, -1, 0}. So the distinction is that we're either considering integers only or all real numbers in this interval. To ensure that we only look at integers, the student would have to write \left\{x| x\in\mathbb{Z}, \ -5 \le x \le 0\right\}. The portion x \in \mathbb{Z} means "x is in the set of integers". The Z refers to the German word Zahlen, which translates to "numbers".
  • C. This is false. The student used the correct inequality signs to indicate x is -5 or larger and also 0 or smaller; basically x is between -5 and 0 inclusive of both endpoints. The "or equal to" portions indicate we are keeping the endpoints and not excluding them.
  • D. This is false. Writing -5 \ge x \ge 0 would not make any sense. This is because that compound inequality breaks down into -5 \ge x \ \text{ and } \ x \ge 0. Try to think of a number that is both smaller than -5 AND also larger than 0. It can't be done. No such number exists.
8 0
2 years ago
The mean crying time of infants during naptime at a local preschool is 12 mins. The school implements a new naptime routine in a
love history [14]

Answer:

Step-by-step explanatio n: ummmoirnd iehcn

7 0
3 years ago
What's the next number in the series. 65536, 256, 16..?
Artemon [7]
Hi there!

Since
65536 =  {256}^{2}
and
256 =  {16}^{2}
, we would need to find
\sqrt{16}
, which is 4.

So, the answer is 4.

Hope this helps!
5 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
2 years ago
I hope this uploaded sorry still having a hard time with this one
Shkiper50 [21]
No problem 72 cubic squares
8 0
2 years ago
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