Answer:
1900
Step-by-step explanation:
P'EMDAS
Given that a flyer begins from earth and thrown up with a velocity of 30 ft/sec vertically.
u = initial velocity = 30 : a = -g = 32 ft/sec^2
s(0) =initial height =4 ft.
We have the equation
where u = initial velocity : v= final velocity : s = distance travelled and a = acceleration. Here final velocity is found out as follows
Substitute to get
Since v cannot be negative, the flyer’s center of gravity cannot ever reach 20 feet.
----------------------------------
To reach 25 ft, put s = 25
and v must be atleast 0
Then we have
Hence if thrown with initial velocity of 40 ft /sec, it will reach a height of 25 ft.
9*(1/x)=33*(1/99)
9/x=1/3
x=27
the number is 27
.5. To get this, multiply 5 x .1
Answer:
f(4) = -11
Step-by-step explanation:
Plug in 4 for x: Note that x = 4.
f(x) = -2x - 3
f(4) = -2(4) - 3
Remember to follow PEMDAS. First, solve the multiplication, then subtract:
f(4) = (-2 * 4) - 3
f(4) = (-8) - 3
f(4) = -11
f(4) = -11 is your answer.
~