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Tema [17]
3 years ago
8

A scientist planted seeds in 4 sections of soil for experiment. Not alll of the seeds grew into the plant .after 20 days, the sc

ientist counted the number of plants in each of the 4 sections.
Mathematics
1 answer:
Karolina [17]3 years ago
3 0
What is the question? no question has been asked. need more info to solve.
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What are the variable terms in the expression 6g-11+5h
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the variable terms are the ones with the letters  6g and 5h

Step-by-step explanation:

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How can you express 11 x 7 using the distributive property?
artcher [175]

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77 < answer

Step-by-step explanation:

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URGENT DUE BY 2:30 WILL RATE GOOD:)
Dmitry [639]
Areashaded=areabigcircle-areasmallcircle


areacircle=pir^2
d/2=r

big diameter=20.4, so radius i 20.4/2=10.2cm

small is 10.8/2=5.4


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7 0
3 years ago
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a. Calculate the volume of the solid of revolution created by rotating the curve y = 3 + 3 exp(-5 x) about the x-axis, for x bet
miskamm [114]

Answer:

A) The volume of solid is 18π cubic unit.

B) The volume of sphere is \dfrac{4}{3}\pi r^3

    a = -r , b = r , f(x)=\sqrt{r^2-x^2} and V=\dfrac{4}{3}\pi r^3

Solution A)

The given curve, y=3+3e^{-5x} rotate about x-axis between 2 to 4.

Please find attachment for solid figure or rotation.

Using disk method to find the volume rotation about x-axis

V=\int_a^b\pi R^2dx  

where, a = 2, b= 4 , R=y=3+3e^{-5x} and dx is thickness of disk.

V=\int_2^4\pi (3+3e^{-5x})^2dx

V=9\pi\int_2^4(1+e^{-10x}+2e^{-5x})dx

V=9\pi(x-\dfrac{1}{10}e^{-10x}-\dfrac{2}{5}e^{-5x})|_2^4)

V=9\pi(4-\dfrac{1}{10}e^{-40}-\dfrac{2}{5}e^{-20}-2+\dfrac{1}{10}e^{-20}-\dfrac{2}{5}e^{-10}))

V=9\pi (2-0)

V=18\pi

Hence, the volume of solid is 18π cubic unit

Solution B)

The equation of circle of radius r and centered at origin (0,0).

x^2+y^2=r^2

y=\sqrt{r^2-x^2}

The solid form is sphere of radius r.

Using disk method, to find volume of solid

V=\int_a^b\pi R^2dx  

where, a = -r, b = r , R=y=\sqrt{r^2-x^2} and dx is thickness of disk.

V=\int_{-r}^r\pi (r^2-x^2)dx

V=\pi(r^2x-\dfrac{x^3}{3})|_{-r}^r

V=\pi(2r^3-\dfrac{2r^3}{3})

V=\dfrac{4}{3}\pi r^3

Hence, the volume of sphere is \dfrac{4}{3}\pi r^3

4 0
4 years ago
On a spinner, there are 10 equal spots,
masha68 [24]

Answer:1/100

Step-by-step explanation:

1/10*1/10

4 0
3 years ago
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