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ivann1987 [24]
3 years ago
6

jacob bought a place mat. The place mat has four sides and only one pair of parallel sides. Which could be the shape of Jacob's

place mat? (
Mathematics
2 answers:
Gwar [14]3 years ago
8 0
A rectangle is the answer 
liq [111]3 years ago
5 0
Possible a trapezoid, since it has only pair of parallel sides and had four sides in total.
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-7x^2+10=185 how to solve
bonufazy [111]

Answer:

-7x²=185-10

-7x²=175

x²=-25

x=±√-25

6 0
2 years ago
F(x) =2^x−4<br> g(x) = 5/x<br><br> evaluate g(f(2))=
Afina-wow [57]

Answer:

not possible

Step-by-step explanation:

f(2)=2^2-4=0

g(f(2))=5/0 it's not possible

8 0
2 years ago
In need help please fast
slava [35]

Answer:

hope it helped u alot

Step-by-step explanation:

plsss give me braniest

8 0
2 years ago
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
I honestly need to know how to take some of my stuff down cause apparently it’s bad to show something‍♀️
Lena [83]

Answer: 40%

Step-by-step explanation:

Total: 760.

304 of 760 as a percentage = 40%.

760 - 304 = 456.

456 of 760 as a percentage = 60%.

7 0
3 years ago
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