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3 years ago

w(-3,3), x(6,4), y(6,-4) z(8,-6) determine weather wx and yz are paralell, perpindicular, or neither. PLEASE PLEEASE HELP ME

Mathematics

1 answer:

djyliett [7]3 years ago

3 0

Answer:

Neither.

Step-by-step explanation:

Parallel lines have equivalent slopes while perpendicular lines have opposite reciprocal slopes. (Opposite meaning different signs and reciprocal meaning flipped fraction)

Ex: 3/4 → -4/3

$wx:~m=\frac{4-3}{6-(-3)}\\wx:~m=\frac{1}{9}\\\\yz:~m=\frac{-6-(-4)}{8-6}\\yz:~m=\frac{-2}{2}\\yz:~m=-1$

These lines are neither parallel nor perpendicular.

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Pie

Answer:

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Step-by-step explanation:

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3 years ago

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sladkih [1.3K]

Answer:

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3 years ago

The amount of time required for an oil and filter change on an automobile is normally distributed with a mean of 45 minutes and

Firdavs [7]

Answer:

$P(39 < X < 48 ) = 0.8767$

95% of all sample means will fall between $40.1 < \mu < 49.9$

$\= x = 41. 795$

$n = 25$

Step-by-step explanation:

From the question we are told that

The mean is $n = 45$

The population standard deviation is $\sigma = 10$

The sample size is n = 16

Generally the standard error of the mean is mathematically represented as

$\sigma_{x} = \frac{ \sigma}{\sqrt{n} }$

=> $\sigma_{x} = \frac{ 10 }{\sqrt{16 } }$

=> $\sigma_{x} = 2.5$

Generally the probability that the sample mean will be between 39 and 48 minutes is

$P(39 < X < 48 ) = P( \frac{ 39 - 45}{ 2.5} < \frac{X - \mu }{\sigma } < \frac{ 48 - 45}{ 2.5} )$

=> $P(39 < X < 48 ) = P(-2.4 < Z< 1.2 )$

=> $P(39 < X < 48 ) = P( Z< 1.2 ) - P(Z < -2.4)$

From the z table the area under the normal curve to the left corresponding to 1.2 and -2.4 is

=> $P( Z< 1.2 ) = 0.88493$

and

$P( Z< - 2.4 ) = 0.0081975$

$P(39 < X < 48 ) = 0.88493 -0.0081975$

=> $P(39 < X < 48 ) = 0.8767$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * 2.5$

=> $E =4.9$

Generally the 95% of all sample means will fall between

$\mu -E < and \mu +E$

=> $45 -4.9\ and \ 45 + 4.9$

Generally the value which 90% of sample means is greater than is mathematically represented

$P( \= X > \= x ) = 0.90$

=> $P( \= X > \= x ) = P( \frac{\= X - \mu }{ \sigma_x} > \frac{\= x -45 }{ 2.5} ) = 0.90$

=> $P( \= X > \= x ) = P( Z > z ) = 0.90$

Generally from the z-table the critical value of 0.90 is

$z = -1.282$

$\frac{\= x -45 }{ 2.5} = -1.282$

=> $\= x = 41. 795$

Considering question 2

Generally we are told that the standard deviation of the mean to be one fifth of the population standard deviation, this is mathematically represented as

$s = \frac{1}{5} \sigma$

Generally the standard deviation of the sample mean is mathematically represented as

$s = \frac{\sigma }{ \sqrt{n} }$

=> $\frac{1}{5} \sigma = \frac{\sigma }{ \sqrt{n} }$

=> $n = 5^2$

=> $n = 25$

5 0

3 years ago

Graph each equation y=7x-7<br><img src="https://tex.z-dn.net/?f=y%20%3D%207x%20-%207" id="TexFormula1" title="y = 7x - 7" alt="y

Dafna1 [17]

to graph a LINEar equation, since it's just a straight line, recall, to draw a straight line all you need is two points.

so we can just pick two random "x" values, hmmmmm say x = 0, what's "y"?

y = 7(0)-7 => y = -7....................................... so that gives us the point (0, -7)

hmmm x = 2, what is "y"?

y = 7(2) - 7 => y = 14-7 => y = 7................. so we get the point (2, 7).

then just plot those, and run a line through them.

6 0

3 years ago

for a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height,

kolbaska11 [484]

Problem

For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground

Solution

We know that the x coordinate of a quadratic function is given by:

Vx= -b/2a

And the y coordinate correspond to the maximum value of y.

Then the best options are C and D but the best option is:

D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a

The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.

7 0

1 year ago