w(-3,3), x(6,4), y(6,-4) z(8,-6) determine weather wx and yz are paralell, perpindicular, or neither. PLEASE PLEEASE HELP ME

Mathematics

1 answer:

djyliett [7]3 years ago

3 0

Answer:

Neither.

Step-by-step explanation:

Parallel lines have equivalent slopes while perpendicular lines have opposite reciprocal slopes. (Opposite meaning different signs and reciprocal meaning flipped fraction)

Ex: 3/4 → -4/3

$wx:~m=\frac{4-3}{6-(-3)}\\wx:~m=\frac{1}{9}\\\\yz:~m=\frac{-6-(-4)}{8-6}\\yz:~m=\frac{-2}{2}\\yz:~m=-1$

These lines are neither parallel nor perpendicular.

You might be interested in

Find a positive number that equals 2 when added to its square.

liberstina [14]

It's 1 haha. one squared is one and add and you get 2

5 0

3 years ago

Write 0.000000364 in standard form

Thepotemich [5.8K]

Answer:

yes

Step-by-step explanation:

this number is a decimal

5 0

3 years ago

Y=-1/2x+10x what is the height of the arch at the turning point

lozanna [386]

your equation is linear, so there isn't any arch

6 0

3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$