Answer is <span>a. d = 26.2 km, C = 82.31 km
D = 2r = 2 x 13.1 = 26.2
C = 2pi r = 2 x </span>3.14159265359 x 13.1
C = 82.31
Answer:
none of the above
Step-by-step explanation:
The problem as written cannot have any of the solutions offered.
For any of those choices, the right side expression will be irrational. The left side expression will be rational for any rational value of x, so cannot be equal to the right-side expression.
The solution is an irrational number near ...
x ≈ 1.33682898582
<h2>
Answer:<em>
</em><em><u>
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
</u></em></h2><h2><em><u>
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>
Step-by-step explanation: The prime factorization of 4320 is
2•2•2•2•2•3•3•3•5
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 4320 = √ 2•2•2•2•2•3•3•3•5 =2•2•3•√ 30 =
± 12 • √ 30
√ 30 , rounded to 4 decimal digits, is 5.4772
So now we are looking at:
w = ( -40 ± 12 • 5.477 ) / -34
Two real solutions:
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757
or:
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
MY HEAD HURTS!
Answer: 5.875 miles run on Friday to reach her goal by Jen
Step-by-step explanation:
Since we have given that
Part of distance covered on Monday by Jen is given by

Part of distance covered on Tuesday by Jen is given by

Part of distance covered on Wednesday by Jen is given by
0
Part of distance covered on Thursday by Jen is given by

Total part of distance covered in these four days by Jen is given by

Remaining part of distance will be covered on Friday to reach her goal which is given by

Hence, 5.875 miles run on Friday to reach her goal by Jen.
Answer: y= 1200 (1.025)^t
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form)
t= years
A = population after t years
Replacing with the values given:
1200= 1200 (1+ 2.5/100)^5
1200= 1200 (1+ 0.025)^5
1200= 1200 (1.025)^5
For the number of rabbits, y, at the end of t years
y= 1200 (1.025)^t
Feel free to ask for more if needed or if you did not understand something.