Answer:
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.
a) Number of different samples = 20C3 = =1140
b) 2 good and one bad chip
Number of samples = 10C2 * 10C1 = 45 * 10 =450
c) 2 good 1 bad + 1 good 2 bad + 3 bad
Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
=
Answer:
1. Five classes in the frequency distribution
2.The mid point of the third class is 24.5
3.The total number of frequency is 100
4.The relative frequency of the third class is (20/100=0.2)
5. We use n-1 because we are dealing with a sample data
6. The mean is 24.5
7. The value of the standard deviation is 11
Step-by-step explanation:
See attached picture for the solutions
Using a system of equation, we have that:
a)
b)
The system is:
c)
The cost of one on-site repair service is of $90.
Item a:
The variables are:
Item b:
On-site service costs <u>3 times as much as at-store service</u>, thus:
By mail service costs <u>$10 less than at-store</u> service, thus:
Last week, the shop completed <u>15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100</u>, thus:
The system is:
Item c:
Then
The cost of one on-site repair service is of $90.
A similar problem is given at brainly.com/question/24823220