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2 years ago

If one of the cars starts and ends at the same point in the race (making a loop around the track), what is the car's

Mathematics

1 answer:

enot [183]2 years ago

8 0

Using it's concept, it is found that the displacement of the car is of 0.

The displacement is given by the change in position, that is, the final position subtracted by the initial position.

In this problem, the car is in a loop, which means that the final position is the same as the initial position.

Hence, a number is subtracted by itself, which means that the displacement is of 0.

A similar problem is given at brainly.com/question/12619606

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Answer:

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2 years ago

Sam ran 63,756 feet in 70 minutes. What is Sam’s rate in miles per hour?

MArishka [77]

Answer:

63756/70=910.8 ft per minute

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3 years ago

10 (2)+1(2) how do u solve this problem?

Ilya [14]

Answer:22

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1 year ago

Read 2 more answers

2. Carl needs 15 hours longer than Jennifer to paint a room. If they work together, they can complete the job in 4 hours. Explai

nasty-shy [4]

Answer:

Jennifer would complete the job on her own in 5 hours.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

Rates

The together rate is the sum of their separates rate.

We have that:

Jennifer takes x hours to complete the job on her own, so her rate is 1/x.

Carl needs 15 hours longer than Jennifer, that is, 15 + x hours, so his rate is 1/(15+x).

The together rate is 1/4. So

$\frac{1}{4} = \frac{1}{x} + \frac{1}{15+x}$

$\frac{1}{4} = \frac{15 + x + x}{x(15+x)}$

$\frac{1}{4} = \frac{15 + 2x}{x(15+x)}$

Applying cross multiplication.

$x^2 + 15x = 4(15 + 2x)$

$x^2 + 15x = 60 + 8x$

$x^2 + 7x - 60 = 0$

Quadratic equation with $a = 1, b = 7, c = -60$ . So

$\Delta = 7^{2} - 4*1*60 = 289$

$x_{1} = \frac{-7 + \sqrt{289}}{2} = 5$

$x_{2} = \frac{-7 - \sqrt{289}}{2} = -12$

Since the time to complete the job has to be a positive value.

Jennifer would complete the job on her own in 5 hours.

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2 years ago

Reduce to simplest form -\dfrac{1}{4}-\left(-\dfrac{3}{5}\right)=−

Arturiano [62]

Hehehehe
Hahaha
Eat eat eat ugly ah glad to help
I did the quiz

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2 years ago