Question

Please someone help me and do not just write anything explain thank you . use the information provided to write the vertex form equation of each parabola.
y= -2x^2-12x-28 I ended up with (6,-64) is that correct? And remember to add 28 to both sides first PPPPPPPPPPPLLLLLZZZ SOOOOOMMMMONE HEEEELP ME

Answer 1

Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c

the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating


y=-2x^2-12x-28
a=-2
b=-12

xvalue of vertex is -(-12)/(2*-2)=12/-4=-3

x value of vertex is -3

plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10

yvalue is -10
x value is -3

vertex is (-3,-10)