The chosen topic is not meant for use with this type of problem. Try the examples below.
Answer:
Component Form: v = <-1,6>
Magnitude of v: ||v|| = √37
Direction of v: θv = 100° (to the nearest degree)
Step-by-step explanation:
Component Form: v = <(5-6),(3-(-3))> = <-1,6>
Magnitude of v: ||v|| = √[(-1)²+(6)²] = √(1+36) = √37
Direction of v: α = tan⁻¹|6/-1| = tan⁻¹|-6| = tan⁻¹(6) = 80.53° which is your reference angle, but to verify that the angle is in the second quadrant, you'll need to do θv = 180° - 80.53° = 99.47°, therefore your direction angle is θv=100° to the nearest degree.
f(x) = (x - 2)^3 + 1
Find the derivative:-
f'(x) = 3(x -2)^2 This = 0 at the turning points:-
so 3(x - 2)^2 =
giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1
Answer is (2, 1)
Answer:
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
since 36=6² and the other option is not square of integer
