6x2-8÷4=_____________

a blue whale weighs about 300,000 pounds, and a great white shark weighs about 4,000 pounds. how many times the weight of a grea

Tanya [424]

300,000 / 4,000 = 75

so the weight of the blue whale is 75 times bigger then the weight of the shark

3 0

3 years ago

Read 2 more answers

Solve for the value of k.

OLEGan [10]

Answer:

The value of K is 5

Step-by-step explanation:

I reversed it.

The tiny squares means 90⁰, so 90+49=139

All of these angles add up to 180⁰

So 180-139=41

The k equation equals 41⁰, so reverse it to find answer

41-1=40

40÷8=5

7 0

2 years ago

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Jane corporation produces model toy cars each sells for $29 99 sense its variable cost per unit is $14 25 sense what is the brea

n200080 [17]

Answer:

Break-even point in units= 20,000

Step-by-step explanation:

Giving the following information:

Selling price per unit= $29.99

Unitary variable cost= $14.25

Fixed costs= $314,800

<u>To calculate the break-even point in units, we need to use the following formula:</u>

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 314,800 / (29.99 - 14.25)

Break-even point in units= 20,000

5 0

3 years ago

The focus of a parabola is (0, -3) and the directrix is y = 3. What is the equation of the parabola?

OleMash [197]

Answer:

The equation of the parabola is $y = -12\cdot x^{2}$ .

Step-by-step explanation:

Since the directrix is of the form $y = a$ , the parabola is vertical. The vertex of the parabola ( $V(x,y)$ ) is the midpoint between the focus ( $F(x,y)$ ) and a point of the directrix ( $P(x,y)$ ), that is to say:

$V(x,y) = \frac{1}{2}\cdot F(x,y) + \frac{1}{2}\cdot P(x,y)$ (1)

If we know that $F(x,y) = (0, -3)$ and $P(x,y) = (0, 3)$ , then the coordinates of the vertex of the parabola:

$V(x,y) = \frac{1}{2}\cdot (0, -3) + \frac{1}{2}\cdot (0, 3)$

$V(x,y) = (0, 0)$

The vertex factor ( $p$ ) is the distance of the focus with respect to the vertex:

$p = \sqrt{[F(x,y)-V(x,y)]\,\bullet \,[F(x,y)-V(x,y)]}$ (2)

If we know that $F(x,y) = (0, -3)$ and $V(x,y) = (0, 0)$ , then the vertex factor is:

$p = \sqrt{0^{2}+(-3)^{2}}$

$p = -3$

The equation of the parabola in the vertex form is described below:

$y - k = 4\cdot p \cdot (x-h)^{2}$ (3)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$h, k$ - Coordinates of the vertex.

If we know that $(h,k) = (0, 0)$ and $p = -3$ , then the equation of the parabola is $y = -12\cdot x^{2}$ .

6 0

2 years ago

Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab

Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected, and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, $H_0$ : $\mu$ = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, $H_1$ : $\mu$ < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 738.44 hours

s = sample standard deviation = 38.2 hours

n = sample size = 50

So, test statistics = $\frac{738.44-750}{\frac{38.2}{\sqrt{50} } }$ ~ $t_4_9$

= -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0

3 years ago

6x2-8÷4=______________