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swat32
4 years ago
14

Solue for n (M+n)/p=r

Mathematics
1 answer:
Eva8 [605]4 years ago
4 0
(M+n)/p=r
Multiply by p
M+n=pr
Minus M
n=pr-M
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If y=3 when x=9 find x when y=1<br> &amp; if y=2 when x=0.5 find y when x=3
hram777 [196]
I got -19/655 and i know for sure this isnt the correct answer.
4 0
4 years ago
Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
4 years ago
The domain is ?<br> The range is ?
DIA [1.3K]

This is a quadratic equation, which is also a polynomial.  Polynomials all have the domain (-infinity, +infinity).

As for the range:  You can see from the graph that the smallest y-value is -2.  Thus, the range is [-2, infinity).

4 0
3 years ago
Suppose that a household's monthly water bill (in dollars) is a linear function of the amount of water the household uses (in hu
dolphi86 [110]

Answer:

The monthly cost for 9 HCF is $38.54

Step-by-step explanation:

<em>The graph is missing; however, the question can still be solved</em>

Given

Slope = 1.55

When monthly cost = $47.84, Amount of water = 15 HCF

Required

Determine the monthly cost for 9 HCF

From the question, we understand that it is a linear function;

Linear functions are of the form

y = mx + b

Where y is the function of x and m is the slope

In this case; the function is the monthly water bill

and x is the amount of water

Solving for b

When monthly cost = $47.84, Amount of water = 15 HCF

The function is as follows;

47.84 = 1.55 * 15 + b

47.84 = 23.25 + b

Subtract 23.25 from both sides

47.84 - 23.25= 23.25 - 23.25 + b

24.59 = b

b = 24.59

Solving for the monthly cost for 9 HCF

Here, we have that

x = Amount\ of\ water = 9

m = Slope = 1.55

b = 24.59

Substitute these values in the linear function; y = mx + b

y = 1.55 * 9 + 24.59

y = 13.95 + 24.59

y = 38.54

<em>Hence, the monthly cost for 9 HCF is $38.54</em>

5 0
3 years ago
I JUST WANNA PASS MY SOPHOMORE YEAR BUT I SUCK AT MATH!!!!! PLEASE HELP!!!!!!
Natasha2012 [34]

Mr. Sanchez's class: 1.65p

Mr. Kelly's class: 1.36j

where p = fruit pies and j = fruit juice

____________________________________________________________

(a) Creating a system of equations

p + j = 79

1.65p + 1.36j = 118.17

are your system of equations

____________________________________________________________

(a) Solving the system of equations for p and j

Solve for p in the first equation. Subtract j from both sides.

p = 79 - j

____________________________________________________________

Plug p into the second equation.

1.65(79 - j) + 1.36j = 118.17

Distribute 1.65 inside the parentheses.

130.35 - 1.65j + 1.36j = 118.17

Combine like terms.

130.35 - 0.29j = 118.17

Subtract 130.35 from both sides.

-0.29j = -12.18

Divide both sides by -0.29.

j = 42

____________________________________________________________

Plug j into the first equation.

p + (42) = 79

Subtract 42 from both sides.

p = 37

____________________________________________________________

(b) To find out how much each class earned

Now plug in p and j into Mr. Sanchez's class and Mr. Kelly's class equations (at the top).

Mr. Sanchez's class: 1.65(37) = 61.05

Mr. Kelly's class: 1.36(42) = 57.12

____________________________________________________________

(c) To see how much more Mr. S's class earned

Subtract 57.12 from 61.05.

61.05 - 57.12 = 3.93

____________________________________________________________

(a)

p + j = 79

1.65p + 1.36j = 118.17

(b)

Mr. Sanchez's class earned more money (61.05 > 57.12).

(c)

Mr. Sanchez's class earned $3.93 more than Mr. Kelly's class.

3 0
3 years ago
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