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2 years ago

Helppppo i will give brainliest!!!

Mathematics

2 answers:

nadya68 [22]2 years ago

8 0

Your answer will be C. Will put explanation in the comments in a few mins.

dangina [55]2 years ago

8 0

Your answer is c and it’s that one because you have to do it because the 2 has to be negative especially if it’s on the x side and the y has to be positive because you already did negative

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3 years ago

One number is four less than a second number. Three times the first is 13 more than 4 times the

Gala2k [10]

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Step-by-step explanation:

5 0

3 years ago

The augmented matrix of a system of equations has been transformed to an equivalent matrix inâ€‹ row-echelon form. Usingâ€‹ x, y

jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a Row Echelon Form, which satisfies the following conditions:

There is a row of all zeros at the bottom of the matrix;
The first non-zero element of any row is 1, which called leading role;
The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

$\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]$ $\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]$

or in system form:

x + 2y + 2z = 4

y + 3z = 9

z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0

4 years ago

When 27x^2z divided by -3x^2z^6 is correctly simplified, the exponent on the variable z is _____.

Dmitry_Shevchenko [17]

The Answer Is YES :D

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3 years ago

Factorise x^2-y^2-2x+6y-8

Talja [164]

X^2 - y^2 - 2x + 6y - 8
= (x^2 - 2x + 1) - (y^2 - 6y + 9) - 8 - 1 + 9 
= (x - 1)^2 - (y - 3)^2 
= [(x - 1) - (y - 3) ] [(x - 1) + (y - 3)] 
= (x - 1 - y + 3) ( x - 1 + y - 3) 
= (x - y + 2) (x + y - 4)

3 0

4 years ago