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3 years ago

Why are all irrational numbers real numbers.

Mathematics

1 answer:

sasho [114]3 years ago

8 0

The irrational number can not be presented as a ratio involving two integers.

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Find the measurement of either the leg or the hypotenuse: A = B = 21 C = 35

Varvara68 [4.7K]

Answer: x = 40.81 or 41

Step-by-step explanation:

A = B = 21

C = 35

Hypotenuse = x

Calculating Hypotenuse:

21^2 + 35^2 = x^2

=> 441 + 1225 = x^2

=> x^2 = 1666

=> x = 40.81 or 41

5 0

3 years ago

Which of the followings explains the difference between a regular subquery and a correlated subquery?

Fynjy0 [20]

Correlated means that they relate so probably this might help

5 0

4 years ago

the dog needs a 1/3 of a cup of dog food each day. the bag holds 5 cups of dog food how many days will it last ?

sleet_krkn [62]

Answer:

15 days

Step-by-step explanation:

You have 5 cups of food, and you give him 1/3 a day.

So, 5 divided by 1/3, which would get you 15 days. Or you could cross-multiply, meaning you multiply across, but in this case I just made them line up so you can see how to do it. $(food)/(cupsperday) = 5/\frac{1}{3} \\OR\\\frac{(food)}{1}*(cupsperday) = \frac{5}{1} *\frac{3}{1}$

7 0

3 years ago

GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?

loris [4]

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

$2n-1=14$

solve for n

$2n=14+1$

$2n=15$

$n=7.5\ cm$

step 2

Find the length of GJ

we know that

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

$GJ=\frac{1}{2}DE$