Use elimination and subtitution method to solve the problem.
First, eliminate x and you'll find the value of y
x - 4y = 12
x - y = 0
--------------- - (substract)
-3y = 12
y = 12/-3
y = -4
Second, subtitute -4 as y and you'll find the value of x
x - y = 0
x- (-4) = 0
x + 4 = 0
x = -4
The solution
x,y = -4,-4
This one was though, but I think it might be y= -1/12x - 53/12.
Hope I helped!
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Answer:
(a) 6² +3² +1² +1² = 47
(b) 5² +4² +2² +1² +1² = 47
(c) 3³ +4² +2² = 47
Step-by-step explanation:
It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.
The approach where a cube is required can work the same way.
(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1
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(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...
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(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2
