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joja [24]
2 years ago
5

Calculate 4,​235 divided by 11

Mathematics
1 answer:
love history [14]2 years ago
5 0

Answer:385

Step-by-step explanation:

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Plz show work <br> 2(x+5)=26
Zolol [24]

Answer:

x = 8

Step-by-step explanation:

Step 1: Write equation

2(x + 5) = 26

Step 2: Solve for <em>x</em>

<u>Distribute 2:</u> 2x + 10 = 26

<u>Subtract 10 on both sides:</u> 2x = 16

<u>Divide both sides by 2:</u> x = 8

8 0
4 years ago
Read 2 more answers
Solve the nonlinear inequality. express the solution using interval notation. (x − 2)(x + 8) &lt; 0 webassign
stepladder [879]
First you find the zeros/x-intercepts using the factors already given in the inequality.

x = 2
x =  - 8

Therefore we make our solution using the interval notation.

- 8 \leqslant x \leqslant 2
8 0
3 years ago
Use multiplication to describe the relationship between the dividend, the divisor and the quotient. Then use that relationship t
Romashka [77]

In a division problem, ...

... dividend / divisor = quotient

Multiplying both sides of this equation by "divisor", we get ...

... dividend = quotient × divisor . . . . . . . . the desired relationship

The for dividend = 1/8, divisor = 6, and quotient = 1/48, this becomes ...

... 1/8 = 1/48 × 6

... 1/8 = 6/48 = 1/8 . . . . . the given values are consistent

3 0
3 years ago
Write and solve an equation for the scenario. Angela rented a car for $29.99 a day plus a one time insurance fee of $5. Her bill
Gnesinka [82]

Answer:

29.99x +5 =124.96 ; x = 4

Step-by-step explanation:

X is how many days. She rented the car for 4 days.

3 0
3 years ago
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A random sample of 10 observations was selected from a normal population distribution. The sample mean and sample standard devia
Delvig [45]

Answer:

18.0167≤x≤21.9833

Step-by-step explanation:

Given the following

sample size n = 10

standard deviation s = 3.2

Sample mean = 20

z-score at 95% = 1.96

Confidence Interval = x ± z×s/√n

Confidence Interval = 20 ± 1.96×3.2/√10

Confidence Interval = 20 ± (1.96×3.2/3.16)

Confidence Interval = 20 ± (1.96×1.0119)

Confidence Interval = 20 ±  1.9833

CI = {20-1.9833, 20+1.9833}

CI = {18.0167, 21.9833}

Hence the required confidence interval is 18.0167≤x≤21.9833

8 0
3 years ago
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