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3 years ago

15

Plz show work 2(x+5)=26

2 answers:

Zolol [24]3 years ago

8 0

Answer:

x = 8

Step-by-step explanation:

Step 1: Write equation

2(x + 5) = 26

Step 2: Solve for <em>x</em>

<u>Distribute 2:</u> 2x + 10 = 26

<u>Subtract 10 on both sides:</u> 2x = 16

<u>Divide both sides by 2:</u> x = 8

mezya [45]3 years ago

6 0

First we have to Distribute 2(x + 5)= 26
When Distributed: 2*x= 2x + 2*5=10
No we lets bring it down 2x+10=26
Now subtract the 10-10 and you get 0.
Subtract 26-10= 16
Now bring the equation down 2x=16
Then we divide both sides by 2 and that would give us 8 as the answer :)

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If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.

Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

<em></em>

Step-by-step explanation:

Given

$f(x)=x^3-12x^2+35x-24$

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Required

Find all zeros of the f(x)

If $f(8) = 0$ then:

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$\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}$

Expand the numerator

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}$

Rewrite as:

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}$

Expand

$\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}$

$\frac{f(x)}{x - 8} = (x - 1)(x - 3)$

Multiply both sides by x - 8

$f(x) = (x - 1)(x - 3)(x - 8)$

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

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