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3 years ago

Plz show work 2(x+5)=26

Mathematics

2 answers:

Zolol [24]3 years ago

8 0

Answer:

x = 8

Step-by-step explanation:

Step 1: Write equation

2(x + 5) = 26

Step 2: Solve for x

Distribute 2: 2x + 10 = 26

Subtract 10 on both sides: 2x = 16

Divide both sides by 2: x = 8

mezya [45]3 years ago

6 0

First we have to Distribute 2(x + 5)= 26
When Distributed: 2*x= 2x + 2*5=10
No we lets bring it down 2x+10=26
Now subtract the 10-10 and you get 0.
Subtract 26-10= 16
Now bring the equation down 2x=16
Then we divide both sides by 2 and that would give us 8 as the answer :)

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3 years ago

There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b

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Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

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Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

a>b>c

$a>b>c>d\\\implies x$

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together $=O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)$

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) $\frac{c}{3}$

Using (1)

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}$

Similarly

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}$

So,

$\frac{c}{3}$

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