9514 1404 393
Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
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1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
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3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
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5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
Answer:
y=0
Step-by-step explanation:
Answer:
0.27 repeating.
Step-by-step explanation:
So to solve this we just have to use division.
1 clearly doesnt go into 3 at least one time, so we can add a decimal point and add a 0 to make it 30.
11 goes into 30 2 times, so we have:
0.2
and 30-22=8
So we can add another 0 and make it 80.
Then 11 goes into 80 7 times. So we have:
0.27
and 80-77=3
So again, add the 0, we have 30.
11 goes into 30 2 times, so:
0.272
and 30-22=8
Add another 0 we get 80.
11 goes into 80 7 times.
So finally, we have:
0.2727.
This is a repeating decimal.
This can be shown as:
0.<u>27</u>
So this is your answer!
I was a bit confused with which one it was on your answer key, but knowing that it is 0.<u>27</u> I am guessing you can chose!
Hope this helps!
The answer is C and brainliest answer please.
Answer:
its in the image below because im too lazy to write it down.
Step-by-step explanation:
