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3 years ago

Multiply————-(b+12)^2

Mathematics

1 answer:

Talja [164]3 years ago

5 0

Use Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

b^2 + 2b * 12 + 12^2

Simplify 12^2 to 144

b^2 + 2b * 12 + 144

Simplify 2b * 12 to 24b

b^2 + 24b + 144

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3m+n=10<br>5m-2n=2<br>what is the answer for this one

svlad2 [7]

Answer:

m = 2

n = 4

Step-by-step explanation:

Ok so to solve this, you want to get it so there is only one variable and then solve that equation. To do this, you can start by doing:

3m + n = 10

multiply both sides by 2

6m + 2n = 20

now, in both of your equations you have 2n so you can add the two equations:

6m + 2n = 20

+ 5m - 2n = 2

11m = 22

divide both sides by 11

m = 2.

Now, plug this value into the original equation, 3m + n = 10:

3 * 2 + n = 10

6 + n = 10

subtract 6 from both sides

n = 4

6 0

3 years ago

the sum of −2x2 + x + 31 and 3x2 + 7x − 8 can be written in the form ax2 + bx + c, where a, b, and c are constants. What is the

Kitty [74]

Answer:

$a+b+c=32$

Step-by-step explanation:

we have

$(-2x^{2} +x+31)+(3x^{2}+7x-8)$

Adds the terms

Group terms that contain the same variable

$(-2x^{2}+3x^{2})+(x+7x)+(31-8)$

Combine like terms

$(x^{2})+(8x)+(23)$

where

$a=1,b=8,c=23$

therefore

$a+b+c=1+8+23=32$

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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