3 years ago

Multiply————-(b+12)^2

Mathematics

1 answer:

Talja [164]3 years ago

5 0

Use Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

b^2 + 2b * 12 + 12^2

Simplify 12^2 to 144

b^2 + 2b * 12 + 144

Simplify 2b * 12 to 24b

b^2 + 24b + 144

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A grocery store sells a 6-pack of bottled water for $3.79, a 9-pack for$4.50, and a 12-pack for $6.89. which package costs the least per bottle?

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What is 20% tip on a bill of 59.61

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about $12

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What is 6,051 x 10^5 written in standard form?

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3 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

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3 years ago