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Marina CMI [18]
3 years ago
15

A bean plant grows at a constant rate for a month. After 10 days, the plant is 25 centimeters tall. After 20 days, the plant is

45 centimeters tall. Which equation models the height of the plant, y, after x days?
Mathematics
1 answer:
wariber [46]3 years ago
5 0
Y = 2x + 5

If you take the height at 10 days, 25 centimeters, after 10 more days the height is 45 centimeters, meaning for those 10 extra days the been plant grown 20 centimeters. Since we're told the plant is growing at a constant rate, this shows the bean plant is growing 2 centimeters per day. We can represent this with y = 2x. (After 10 days, the bean plant will be 20 centimeters, after 20 days, the bean plant will be 40 centimeters, etc.)

However, this is not completely true yet. As you can see, after the first 10 days the plant is not 20 centimeter, it's 25 centimeters. We already know the rate in which the plant is changing, but now we need to find the height that the plant was originally, before it started growing.

After the first 10 days, the plant is 25 centimeters tall. Since we know that the plant is growing 2 centimeters per day, we can subtract 20 from 25 to find the original height of the bean plant.

25 - 20 = 5
The bean plant was originally 5 centimeters.

This makes our final equation y = 2x + 5.
2x is the slope, and 5 is the y intercept.

Hope this helps1!
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Answer:

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dh/dt  =  -  0,125 in/min

Step-by-step explanation:

The area of the top is At :

At = π*r²

a)  Tacking derivatives with respect to time:

dAt/dt  =  2* π*r * dr/dt

At   t  =  t₁      r  = 16 in     and  dr/dt =  0,5

Then

dAt/dt  =  2*3,14*16*0,5   in/min

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b) The volume of the cylinder is:

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Tacking derivatives with respect to time

dVc/dt  =  2* π*r*h*dr/dt  +  π*r²*dh/dt

But  dVc/dt  = 0  since the volume remains constant, then:

π*r²*dh/dt  = -  2* π*r*h*dr/dt

r*dh/dt  =  -  2*h*dr/dt

dh/dt  = - 2*0,5*2/16  in/min

dh/dt  =  -  0,125 in/min

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Answer:

C=24π

Step-by-step explanation:

C=2πr

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≈75.39

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The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.

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The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.

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<em>V' ≈</em> 763407.015 ft³

The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium. \blacksquare

To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/13338592

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