Please help thanks <33

Enlarge shape a by 1/3 with the centre enlargement (3,-3) <br> (-9,9) (-9,6) (-3,6)

NemiM [27]

Answer:

0033

Step-by-step explanation:

.033 of a whole number so its .033

5 0

3 years ago

Click in the appropriate box to indicate the match of each table of values to its

taurus [48]

Answer:

ndjdjndbdhskmsbsiwkhsusnsgs

8 0

3 years ago

1.Mike buys an item with a price of $15 and uses a 10% off coupon. How much does he save by using this coupon?

Eva8 [605]

Answer:

14.31

Step-by-step explanation:

7 0

3 years ago

Cheryl collected data for her mathematics project. She noted that the data set was approximately normal.

nadya68 [22]

Answer:

$X_(r) >> X_(n)$

The mean for this case would increase since is defined as:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The interquartile range would not change since the definition for the IQR is $IQR =Q_3 -Q_1$ and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

Step-by-step explanation:

For this case we assume that we have a random sample given $X_(1), X_(2) ,..., X_(n)$ and for each observation $X_i \sim N(\mu, \sigma)$ since the problem states that the data is approximately normal.

Let's assume that the largest value on this sample is $X_(n)$ and for this case we are going to replace this value by another one extremely higher so we satisfy this condition:

$X_(r) >> X_(n)$

The mean for this case would increase since is defined as:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

The interquartile range would not change since the definition for the IQR is $IQR =Q_3 -Q_1$ and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

6 0

3 years ago

Earl when to the store and realize he had 7 more Nickles in his pocket then he thought he had. If all the change in earl’s pocke

Feliz [49]

Answer:

40 nickles

Step-by-step explanation:

Here is the correct question: Earl went to the store and realize he had 7 more Nickles in his pocket then he thought he had; If all the change in earl’s pocket is nickles, he had $2.35 in his pocket, how many more nickles did he think were in his pocket ?

Given: All Nickles in the Earl´s pocket is $2.35.

Remember, 1 Nickles = $.05

∴ Converting the dollar to nickels

$2.35= $\frac{\$ 2.35}{\$ .05} = 47 \ nickels$

Earl had total 47 nickels in his pocket.

∴ Earl earlier had nickles = $47-7= 40 \ nickles$

∵ we know Earl had realized that he had 7 more nickles in his pocket, which means he already had 40 nickles to make $2.35.

4 0

3 years ago