Helppppppp meee plsss

What are the coordinates of the endpoints of the midsegment for △XYZ that is parallel to XZ⎯⎯⎯⎯⎯ ?

Ksenya-84 [330]

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Step-by-step explanation:

In a triangle the segment which joining the mid points of two sides:

Parallel to the 3rd side
Its length is equal half the length of the 3rd side
It's called the mid-segment of the triangle

In Δ XYZ

∵ Vertex X is (0 , 7)

∵ Vertex Y is (2 , 5)

∵ Vertex Z is (0 , 1)

∵ The mid-segment of Δ XYZ is parallel to XZ

- The mid-segment intersects the other two sides of the Δ

at their mid-points

∴ The mid-segment intersects XY and YZ at their midpoints

∴ The endpoints of the mid-segment are the midpoints of

XY and YZ

The mid point of a segments whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

∵ X = (0 , 7) and Y = (2 , 5)

∴ $x_{1}$ = 0 and $x_{2}$ = 2

∴ $y_{1}$ = 7 and $y_{2}$ = 5

∵ The mid point of XY = $(\frac{0+2}{2},\frac{7+5}{2})$

∴ The mid point of XY = $(\frac{2}{2},\frac{12}{2})$

∴ The mid point of XY = (1 , 6)

∵ Z = (0 , 1) and Y = (2 , 5)

∴ $x_{1}$ = 0 and $x_{2}$ = 2

∴ $y_{1}$ = 1 and $y_{2}$ = 5

∵ The mid point of ZY = $(\frac{0+2}{2},\frac{1+5}{2})$

∴ The mid point of ZY = $(\frac{2}{2},\frac{6}{2})$

∴ The mid point of ZY = (1 , 3)

∵ The endpoints of the mid-segment are the midpoints of

XY and YZ

∴ The end points of the mid segments are (1 , 6) and (1 , 3)

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Learn more:

You can learn more about the mid-point in brainly.com/question/5223123

#LearnwithBrainly

7 0

3 years ago

Jordan wants to measure a length of fabric, but the only tape measure she has is damaged. The first number on her tape measure i

Alex

Djdjxkdjdkdkdjddjdjdj yuppppppppp 37387(5y6666+4)WEI

7 0

2 years ago

I need help with this problem plzzz

Effectus [21]

Not sure sorry but you can. Try searching on google or yahoo answers

6 0

3 years ago

Which graph is the result of reflecting f(x) = (8)* across the y-axis and then across the x-axis? O 8- 6- 8 7

marta [7]

I assume you meant $f(x)=8^x$ .

Reflecting across the x-axis would give $y=-8^x$ .

Reflecting across the y-axis would give $y=8^{-x}$ .

8 0

2 years ago

PLEASE HELP ME

balandron [24]

Answer:

The sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.

Explanation:

By inspection (watching the figure), you can tell that to transform the triangle XY onto triangle X"Y"Z", you must slide the former 5 units to the left, 1 unit down, and, finally, reflect it across the x-axys.

You can check that analitically

Departing from the triangle: XYZ

Translation 5 units to the left: (x,y) → (x - 5, y)

Vertex X: (-6,2) → (-6 - 5, 2) = (-11,2)

Vertex Y: (-4, 7) → (-4 - 5, 7) = (-9,7)

Vertex Z: (-2, 2) → (-2 -5, 2) = (-7, 2)

Translation 1 unit down: (x,y) → (x, y-1)

(-11,2) → (-11, 2 - 1) = (-11, 1)

(-9,7) → (-9, 7 - 1) = (-9, 6)

(-7, 2) → (-7, 2 - 1) = (-7, 1)

Reflextion accross the x-axis: (x,y) → (x, -y)

(-11, 1) → (-11, -1), which are the coordinates of vertex X"

(-9, 6) → (-9, -6), which are the coordinates of vertex Y""

(-7, 1) → (-7, -1), which are the coordinates of vertex Z"

Thus, in conclusion, it is proved that the sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.

7 0

3 years ago