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Svetach [21]
3 years ago
13

Helppppppp meee plsss

Mathematics
1 answer:
jonny [76]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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What are the possible numbers of positive, negative, and complex zeros of f(x) = x6 − x5 − x4 + 4x3 − 12x2 + 12?
FrozenT [24]
Using <span>Descartes' rule of signs.
There are 4 changes of signs of coefficients:
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Therefore, there are 4,2 or 0 positive roots </span><span><span>at most</span>. So it must be the third answer.
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dexar [7]

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hope this helps!!! (:


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