Answer:
0.018 is the probability that a randomly selected college student has an IQ greater than 131.5
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 15
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
a) P(IQ greater than 131.5)
P(x > 131.5)
Calculation the value from standard normal z table, we have,
0.018 is the probability that a randomly selected adult has an IQ greater than 131.5
If the ratio is 4:3:2 each part of that ratio has a value of:
216/(4+3+2)
216/9=24
Since A pays four parts,
A pays 4*24=£96
Answer:
1 and 1/25
Step-by-step explanation:
angle A = 30
(2x-9) = (2x+21)
+9 +9
2x=2x+30
-2x -2x
=30