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natali 33 [55]
3 years ago
11

Find the 6th term of a geometric sequence with t1=5 and r = -1/2

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0
Same as before, to make the formula do

t(1) * (r)^n-1
So 5 * (-1/2)^n-1
Therefore 
5*(-1/2)^5
0.078125

Inessa [10]3 years ago
7 0
\bf n^{th}\textit{ term of a geometric sequence}\\\\
t_n=t_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
t_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
n=6\\
t_1=5\\
r=-\frac{1}{2}\\
\end{cases}\implies t_6=5\left(-\frac{1}{2}  \right)^{6-1}
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